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forsale [732]
2 years ago
6

What is the work of an architecture engineer?​

Engineering
2 answers:
lesantik [10]2 years ago
7 0

Answer:

Architectural engineers apply science and technology to the real world by designing buildings that enhance our standard of living and improve our quality of life. They do this by combining building systems – structural, electrical, mechanical, lighting, acoustics and fire protection - into an integrated whole.

expeople1 [14]2 years ago
3 0

Architecture engineer focuses it's study on the designs of all buildings system,including the mechanical, lighting/ electrical and structural systems of a building, while also planning the construction process of buildings and building systems.

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Give five general principles involved in the process of sewage filtration?​
aleksandr82 [10.1K]

Answer:

Some general principles are given below in the explanation segment.

Explanation:

Sewage treatment seems to be a method to extract pollutants from untreated sewage, consisting primarily of domestic sewage including some solid wastes.

<u>The principles are given below:</u>

  • Unless the components throughout the flow stream become greater than the ports or even the gaps throughout the filter layer, those holes would be filled as either a result of economic detection.
  • The much more common element of filtration would be the use of gravity to extract a combination.
  • Broadcast interception or interference.  
  • Inertial influence.
  • Sieving seems to be an excellent method to distinguish particulates.

8 0
3 years ago
You are investigating surface hardening in iron using nitrogen gas. Two 5 mm thick slabs of iron are separately exposed to nitro
Luden [163]

Answer and Explanation:

The explanation is attached below

4 0
3 years ago
How would I get this python code to run correctly? it's not working.​
Elanso [62]

Answer:

See Explanation

Explanation:

This question requires more information because you didn't state what the program is expected to do.

Reading through the program, I can assume that you want to first print all movie titles then prompt the user for a number and then print the move title in that location.

So, the correction is as follows:

Rewrite the first line of the program i.e. movie_titles = ["The grinch......."]

for each_movie_titles in movie_titles:

   print(each_movie_titles)

   

usernum = int(input("Number between 0 and 9 [inclusive]: "))

if usernum<10 and usernum>=0:

   print(movie_titles[usernum])

Line by line explanation

This iterates through the movie_titles list

for each_movie_titles in movie_titles:

This prints each movie title

   print(each_movie_titles)

This prompts the user for a number between 0 and 9    

usernum = int(input("Number between 0 and 9 [inclusive]: "))

This checks for valid range

if usernum<10 and usernum>=0:

If number is valid, this prints the movie title in that location

   print(movie_titles[usernum])

6 0
3 years ago
Come and look on my attachment​
CaHeK987 [17]

Crazy Guy what do uh mean ?

4 0
2 years ago
Based on experimental observations, the acceleration of a particle is defined by the relationa = -( 0.1 + sin(x/b) ),where a and
yKpoI14uk [10]

Answer:

a) v = +/- 0.323 m/s

b) x = -0.080134 m

c) v = +/- 1.004 m/s

Explanation:

Given:

                             a = - (0.1 + sin(x/b))

b = 0.8

v = 1 m/s @ x = 0

Find:

(a) the velocity of the particle when x = -1 m

(b) the position where the velocity is maximum

(c) the maximum velocity.

Solution:

- We will compute the velocity by integrating a by dt.

                           a = v*dv / dx =  - (0.1 + sin(x/0.8))

- Separate variables:

                           v*dv = - (0.1 + sin(x/0.8)) . dx

-Integrate from v = 1 m/s @ x = 0:

                          0.5(v^2) = - (0.1x - 0.8cos(x/0.8)) - 0.8 + 0.5

                          0.5v^2 =  0.8cos(x/0.8) - 0.1x - 0.3

- Evaluate @ x = -1

                          0.5v^2 = 0.8 cos(-1/0.8) + 0.1 -0.3

                          v = sqrt (0.104516)

                          v = +/- 0.323 m/s

- v = v_max when a = 0:

                           -0.1 = sin(x/0.8)

                             x = -0.8*0.1002

                             x = -0.080134 m

- Hence,

                            v^2 = 1.6 cos(-0.080134/0.8) -0.6 -0.2*-0.080134

                            v = sqrt (0.504)

                            v = +/- 1.004 m/s

4 0
3 years ago
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