The resistance R of a wire is given by:

where

is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire.
For the wire in the problem, the resistivity is (copper resistivity)

. The length of the wire is L=1.3 m, while the cross-sectional area is

so the resistance of the wire is:
A.the composition of the inner and outer planets, current observations of star formation, and the motion of the solar system I hope this helps
Answer:
Explanation:
Given
Initial velocity u = 200m/s
Final velocity = 4m/s
Distance S = 4000m
Required
Acceleration
Substitute the given parameters into the formula
v² = u²+2as
4² = 200²+2a(4000)
16 = 40000+8000a
8000a = 16-40000
8000a = -39,984
a = - 39,984/8000
a = -4.998m/s²
Hence the acceleration is -4.998m/s²
Thomas Edison is the answer im 100% sure of it.
Answer:
31
Explanation:
Given:
U=3
X=4
Y=7
u + xy
Substitute the given values to the equation:
3 + (4)(7)
3 + 28
31