Answer : The molarity of solution is, 1.216 g/mole
Explanation : Given,
Density of acetic acid = 1.049 g/ml (standard value)
Volume of acetic acid = 16.00 ml
Volume of solution = 230.0 ml
Molar mass of acetic acid 
= 
First we have to calculate the mass of acetic acid.
Now we have to calculate the molarity of solution.
Therefore, the molarity of solution is, 1.216 g/mole
Answer:
100 g
Explanation:
We know the concentration is 200 g/L.
Convert 500mL to L: 500mL/1000mL = 0.5 L
Now, multiply this by 200 to cancel out the L units and get grams:
200 g/L * 0.5 L = 100 g
Thus, the answer is 100 grams.
Hope this helps!
Given which are missing in your question:
the flask is filled with 1.45 g of argon at 25 C°
So according to this formula (Partial pressure):
PV= nRT
first, we need n, and we can get by substitution by:
n = 1.45/mass weight of argon
= 1.45 / 39.948 = 0.0363 mol of Ar
we have R constant = 0.0821
and T in kelvin = 25 + 273 = 298
and V = 1 L
∴ P * 1 = 0.0363* 0.0821 * 298 = 0.888 atm
Carbon and iron alloys are called steel.
