Answer:
HClO₃ /chloric acid /suffix -ic/ ClO₃⁻ (chlorate)
HClO₂/ chlorous acid/ suffix -ous/ ClO₂⁻ (chlorite)
HNO₃ /nitric acid /suffix -ic/ NO₃⁻ (nitrate)
HNO₂/ nitrous acid/ suffix -ous/ NO₂⁻ (nitrite)
Explanation:
Chlorine has 4 positive oxidation numbers to form oxyacids: +1, +3, +5 and +7.
- When it uses the oxidation number +5, it forms HClO₃, which is named chloric acid, with the suffix -ic. When it loses an H⁺, it forms the oxyanion ClO₃⁻ (chlorate).
- When it uses the oxidation number +3, it forms HClO₂, which is named chlorous acid, with the suffix -ous. When it loses an H⁺, it forms the oxyanion ClO₂⁻ (chlorite).
Nitrogen has 2 positive oxidation numbers to form oxyacids: +3 and +5.
- When it uses the oxidation number +5, it forms HNO₃, which is named nitric acid, with the suffix -ic. When it loses an H⁺, it forms the oxyanion NO₃⁻ (nitrate).
- When it uses the oxidation number +3, it forms HNO₂, which is named nitrous acid, with the suffix -ous. When it loses an H⁺, it forms the oxyanion NO₂⁻ (nitrite).
Answer:
2m/s²
Explanation:
When an object starts or at its state of rest it has an Initial speed U = 0
Final speed = 6m/s
total time taken for the acceleration = 3s
Acceleration =?
Acceleration is the change in velocity (speed) with time
OR
Time rate of change of velocity
Acceleration = <u>Change in Speed(velocity)</u>
Time taken
Hence,
Acceleration = <u> </u><u> </u><u>V - </u><u>U</u><u> </u><u> </u>
t
a = <u>6</u><u> </u><u>-</u><u> </u><u>0</u>
3
a = <u>6</u><u> </u><u> </u>
3
a = 2m/s²
Answer:
Zinc
The element was probably named by the alchemist Paracelsus after the German word Zinke (prong, tooth).
Explanation:
the answer is 15.
4+4+4+1 =13 then u add the 2 outside the bracket which will give u 15
<h3>Answer:</h3>
36 moles of Hydrogen
<h3>Solution:</h3>
The molecular formula of Glucose is,
C₆H₁₂O₆
As clear from molecular formula, each mole of Glucose contains 12 moles of Hydrogen atoms.
Therefore,
1 mole of C₆H₁₂O₆ contains = 12 moles of Hydrogen
So,
3.0 moles of C₆H₁₂O₆ will contain = X moles of Hydrogen
Solving for X,
X = (3.0 mol × 12 mol) ÷ 1 mol
X = 36 moles of Hydrogen
