The period of the pendulum is given by the following equation
T = 2π * sqrt (L/g)
Where g is the gravity (free fall acceleration)
L is the longitude of the pendulum
T is the period.
We find g.............> (T /2π)^2 = L/g
g = L/(T /2π)^2...........> g = 22.657 m/s^2
(a) At its maximum height, the ball's vertical velocity is 0. Recall that

Then at the maximum height
, we have


(b) The time the ball spends in the air is twice the time it takes for the ball to reach its maximum height. The ball's vertical velocity is

and at its maximum height,
so that


which would mean the ball spends a total of about 5.6 seconds in the air.
(c) The ball's horizontal position in the air is given by

so that after 5.6 seconds, it will have traversed a displacement of


Answer:
a) 15.78 mi/h/s
b) 7.105 m/s^2
Explanation:
a) It is given that speed changes from 0 to 60 miles per hour (mph)
Acceleration is equal to change in speed divided by time
mi/h/s
b)
1 mile/h = 0.45 m/s
Acceleration in m/s^2
m/s^2
Answer:
(c) increase by a factor of four
Explanation:
energy = power x time, and power = resistance x current ^2. 2^2 = 4.