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Aleks04 [339]
3 years ago
7

Calculate the mass percent of carbon in the following molecule: Mn3[Mn(CO)4]3

Chemistry
1 answer:
Lilit [14]3 years ago
3 0

Answer:

21.63 %

Explanation:

The molar mass of Mn₃[Mn(CO)₄]₃ is 665.64 g/mol.

Let's assume we have 1 mol of Mn₃[Mn(CO)₄]₃, if that were the case then we would have 665.64 grams.

There are 12 C moles per Mn₃[Mn(CO)₄]₃, with that in mind we<u> calculate the weight of 12 C moles:</u>

  • 12 mol C * 12 g/mol = 144 g

Finally we <u>calculate the mass percent of carbon</u>:

  • 144 g / 665.64 g * 100% = 21.63 %
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