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sdas [7]
3 years ago
8

Heather and Jerry are standing on a bridge 51 m above a river. Heather throws a rock straight down with a speed of 17 m/s . Jerr

y, at exactly the same instant of time, throws a rock straight up with the same speed. Ignore air resistance.
How much time elapses between the first splash and the second splash?
Physics
2 answers:
Step2247 [10]3 years ago
3 0
Jerry throws his rock up at 20 m/s. It will decelerate at the rate of 9.8 m/s^2, until it's velocity reaches zero. At that time it will reach apogee, and begin falling. So (20 m/s)/(9.8m/s^2) =2.04 seconds To reach max height. 

<span>After 2.04 seconds it will begin accelerating downward, again by 9.8m/s^2. So after another 2.04 seconds, it will be at the starting point, traveling at 20 m/s. It will then follow the same time path as Heather's rock. </span>

<span>So Jerry's rock will take 4.08 seconds longer than Heather's to hit the water. The height above the water is not necessary information for this problem.</span>
postnew [5]3 years ago
3 0
Hello there.
<span>
Heather and Jerry are standing on a bridge 51 m above a river. Heather throws a rock straight down with a speed of 17 m/s . Jerry, at exactly the same instant of time, throws a rock straight up with the same speed. Ignore air resistance.
How much time elapses between the first splash and the second splash?
</span>
 4.08
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