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AfilCa [17]
3 years ago
12

During the nineteenth century, biologists knew that South America and Africa contained similar fossils. These fossils led them t

o believe that a temporary land bridge between South America and Africa allowed
ancient species to move between both continents. In the twentieth century, evidence showed that South America and Africa were once part of the same larger continent and that there were no land bridges
between them. How should biologists respond to the new geological finding?

A) Biologists should reject the geological finding, because it is new.
B) Biologists should ask physicists what to do, because physics is a more exact science.
C) Biologists should reject the belief in ancient species, because there were no land bridges.
D) Biologists should update the history of life, because it should include the new geological finding.
Chemistry
1 answer:
Minchanka [31]3 years ago
8 0

Answer:

D

Explanation:

someone in the comments said it lol

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D. Photosynthesis uses carbon dioxide while cellular produces carbon dioxide

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A gas occupies 2.22 l at 3.67 atm. what is the volume at 1.94 atm?
Iteru [2.4K]
According to Boyle's law, volume is inversely proportional to pressure. thus P=k/V
Therefore PV=k
P1V1=P2V2
In the question above,
P1=3.67atm
P2=1.94atm
V1=2.22L
V2=?
Thus substituting for the values in the gas equation;
3.67atm*2.22L=1.94atm*V2
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What is 6.3cm =____mm please help me
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Identify the oxidizing agent and the reducing agent in the reaction. 8H +( aq) + Cr 2O 7 2–( aq) + 3SO 3 2–( aq) → 2Cr 3+( aq) +
S_A_V [24]

Answer:

SO₃²⁻ is the reducing agent and Cr₂O₇²⁻ is the oxidizing agent.

Explanation:

Oxidation reaction:

3SO₃²⁻ (aq) + 3H₂O (l) → 3SO₄²⁻ (aq) + 6H⁺ (aq) + 6e⁻                  

Reduction reaction:

Cr₂O₇²⁻ (aq) + 14H⁺ (aq) + 6e⁻ → 2Cr ³⁺ (aq) + 7H₂O (l)

Now, adding the oxidation and the reduction reactions we get the full net reaction:

Cr₂O₇²⁻ (aq) + 3SO₃²⁻ (aq) + 8H⁺ (aq) → 2Cr ³⁺ (aq) + 3SO₄²⁻ (aq) + 4H₂O(l)

Since, the S in SO₃²⁻, present in the +4 oxidation state is oxidized to +6 oxidation state in SO₄²⁻, by the loss of 2e⁻.

<u>Therefore, SO₃²⁻ is the reducing agent. </u>

And, the Cr in Cr₂O₇²⁻, present in the +6 oxidation state is getting reduced to +3 oxidation state, Cr ³⁺, by the gain of 6e⁻.

<u>Therefore, Cr₂O₇²⁻ is the oxidizing agent.</u>

3 0
3 years ago
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