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crimeas [40]
3 years ago
9

If an object has a mass of 47 kg and it is moved 27 meters in 60 seconds, how much power was used?

Physics
1 answer:
Tamiku [17]3 years ago
5 0

Answer: 207 W

Explanation: I assumed here that the object is moved vertically. If that is the case, the work done on the object is equal to its change in gravitational potential energy:

where

m = 47 kg is the mass of the object

g = 9.8 m/s^2 is the acceleration of gravity

is the change in height

Substituting,

Now we can calculate the power used, which is given by

Hope this helps I'm sorry if i'm wrong but I tried :(

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While in a car at 4.47 meters per second a passenger drops a ball from a height of 0.70 meters above the top of a bucket how far
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s_y=u_yt+\dfrac{1}{2}gt^2\\\Rightarrow 0.7=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{0.7\times 2}{9.81}}\\\Rightarrow t=0.38\ \text{s}

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