Answer:
the answer is c testable
motion energy
Explanation:
motion wnergy is the sum of potential and kinetic energy
And the bigger intensity
Given: V=12 V
I=2.5 mA
Let the resistance be R
By Ohm's Law,
V=IR
12=2.5×10−3R
R=4.8×103 Ω
Ff=μN=μmg=0.8*300*10=2400 N