Barium forms cation : Ba²⁺
<h3>Further explanation</h3>
Given
Barium element
Required
Ion type
Solution
Barium with the symbol Ba is an alkaline earth metal element having the atomic number 56
Electron configuration of Barium: [Xe] 6s2
If we look at this configuration, then Barium will try to achieve stability by removing 2 electrons so that the electron configuration is the same as the noble gas Xenon (Xe)
Because it removes 2 electrons, Barium has the number of protons> the number of electrons so that the charge is positive and forms a cation
<span>KCl<span>O3</span><span>(s)</span>+Δ→KCl<span>(s)</span>+<span>32</span><span>O2</span><span>(g)</span></span>
Approx. <span>3L</span> of dioxygen gas will be evolved.
Explanation:
We assume that the reaction as written proceeds quantitatively.
Moles of <span>KCl<span>O3</span><span>(s)</span></span> = <span><span>10.0⋅g</span><span>122.55⋅g⋅mo<span>l<span>−1</span></span></span></span> = <span>0.0816⋅mol</span>
And thus <span><span>32</span>×0.0816⋅mol</span> dioxygen are produced, i.e. <span>0.122⋅mol</span>.
At STP, an Ideal Gas occupies a volume of <span>22.4⋅L⋅mo<span>l<span>−1</span></span></span>.
And thus, volume of gas produced = <span>22.4⋅L⋅mo<span>l<span>−1</span></span>×0.0816⋅mol≅3L</span>
Note that this reaction would not work well without catalysis, typically <span>Mn<span>O2</span></span>.
It’s because new discoveries are made all the time sometimes what was considered right may be found out to be wrong
