The answer is d. I hope that helps.
Exothermic is the answer to your question
F=ma so a=F/m
ax=180/270=0.67m/s^2
ay=390/270=1.44m/s^2
Magnitude = sqrt((0.67^2)+(1.44^2))=1.59m/s^2
Direction- Tan(x)=0.67/1.44=0.47 Tan^-1(x)=25 degrees
Let's take the positive x-direction towards east and the positive y-direction towards south. The momentum must be conserved on both directions, after the collision. On the x-direction, initially we have only momentum from car 1, while on the y-direction initially only car 2 contributes to the total momentum of the system. After the collision, the two cars will move together with a total mass (m1+m2) and with final velocity vf, which can be decomposed on both directions. All of this translates into the equations:
(1)
(2)
where
,
,
and
.
and
are the components of the final velocity on both axes x and y.
By dividing equation (2) by (1), we get:
And the tangent of this ratio gives exactly the angle of the velocity vf in the south-east direction, with respect to the positive x-axis, so it gives us the direction of the final velocity: