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Romashka-Z-Leto [24]
3 years ago
11

What is the length x of the side of the triangle below

Physics
2 answers:
Shalnov [3]3 years ago
8 0

Answer:

you didn't post any triangles. Thus, the question could not be answered.

alexdok [17]3 years ago
7 0

Answer:

The given triangle is a right triangle.

The length of the hypotenuse is 2.52.5 units.

The given angle is 39\degree39° .

The unknown side xx is adjacent to the given angle.

We can therefore use the cosine function to find xx .

Recall the mnemonics CAH.

This means that;

\cos\theta=\frac{Adjacent}{Hypotenuse}cosθ=

Hypotenuse

Adjacent

This implies that,

\cos39\degree=\frac{x}{2.5}cos39°=

2.5

x

We multiply both sides by 2.52.5 to get,

2.5\cos39\degree=x2.5cos39°=x

x=2.5(0.7771)x=2.5(0.7771)

We evaluate to get

x=1.94x=1.94

Therefore the length xx of the side of the triangle is 1.91.9 units to the nearest tenth.

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The magnitude of the force acting on the object lying on a flat surface without moving is 10 N.

The given parameters;

  • magnitude of force on the object, F = 10 N
  • angle between the object and the horizontal flat surface = 0⁰

Apply Newton's second law of motion to determine the magnitude of the force on the object.

Due to the position of the object, the magnitude of the force acting on it is calculated as;

\Sigma F_{net} = F\sin(\theta ) + F cos(\theta)\\\\\Sigma F_{net} = 10 sin(0) + 10cos(0)\\\\\Sigma F_{net} = 10 \ N

Therefore, the magnitude of the force acting on the object is 10 N.

Learn more here: brainly.com/question/19887955

7 0
2 years ago
A car was moving a 14 m/s. After 30 seconds, it’s speed increased to 20 m/s. What was its acceleration during this time?
Anuta_ua [19.1K]

Answer:

acceleration = 0.2 m/s/s

Explanation:

initial velocity u = 14

final velocity v = 20

time = 30

acceleration = ?

v = u + at

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30a = 6

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5 0
3 years ago
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The trajectory of a projectile always ________________.
sattari [20]

Answer:

c) curves downward, below the initial velocity vector

Explanation:

A projectile is usually launched from a height, where it is launched with an initial velocity. From that point the gravitational force begins to act on the projectile causing it to decay. As time passes, the projectile advances but its height decreases. So its trajectory is curved downward, below the initial velocity vector.

8 0
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Contrary to popular belief, a ski jumper does not achieve a large amount of "air" when doing a jump (less than 6 feet). This is
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Answer:

The vertical distance that the ski jumper fell is 417.45 m.

Explanation:

Given;

initial horizontal velocity of the jumper, V_x = 26 m/s

horizontal distance of the jumper, dx = 240 m

The time of the motion is given by;

dx = Vₓt

t = dx / Vₓ

t = 240 / 26

t = 9.23 s

The vertical distance traveled by the diver is given by;

d_y = V_yt + \frac{1}{2}gt^2

initial vertical velocity, V_y, = 0

d_y =  \frac{1}{2}gt^2\\\\d_y = \frac{1}{2}(9.8)(9.23)^2\\\\d_y = 417.45 \ m

Therefore, the vertical distance that the ski jumper fell is 417.45 m.

6 0
3 years ago
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n200080 [17]

Answer:

the last one

Explanation:

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