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VikaD [51]
3 years ago
9

In the electrolysis of water, how long will it take to produce 75.00 L of H2 at 1.0 atm and 273 K using an electrolytic cell thr

ough which the current is 205.0 mA
Chemistry
1 answer:
IrinaK [193]3 years ago
7 0

answer is 2546 h

mark me as Branliest

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The answer is -- False

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The empirical formula for a compound that is 1.2% h, 42.0%cl, and 56.8%o is
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Hope you understand how to work out those types of questions now xD ;)

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The conversion of glucose-6-phosphate to fructose-6-phosphate is catalyzed by an isomerase enzyme. Glucose-6-phosphate was mixed
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4 years ago
A rubber ball is held 4.0 m above a concave spherical mirror with a radius of curvature of 1.5 m. At time equals zero, the ball
exis [7]

The time elapsed when the ball placed above the concave mirror and the image formed would be at the same location is 0.55 s.

<h3>Image distance</h3>

The position of the image formed is determined using the followimg mirror formula;

\frac{1}{f} = \frac{1}{v} + \frac{1}{u}

where;

  • f is the focal length of the mirror
  • v is the image distance
  • u is the object distance

f = R/2

f = 1.5/2

f = 0.75 m

When the ball and its image is in the same position, u = v

The position of the ball is calculated as;

\frac{1}{f} = \frac{1}{u} + \frac{1}{u} \\\\\frac{1}{f} = \frac{2}{u} \\\\u = 2f\\\\u = 2(0.75)\\\\u = 1.5 \ m

<h3>Time of motion of the ball</h3>

The time taken for the ball to travel the caluclated distance is determined as;

h = ut + ¹/₂gt²

1.5 = 0  + ¹/₂(9.8)t²

1.5 = 4.9t²

t² = 1.5/4.9

t² = 0.306

t = 0.55 s

Thus, the time elapsed when the ball and its image are at the same location is 0.55 s.

Learn more about concave mirror here: brainly.com/question/7512320

8 0
2 years ago
Can someone tell me if I did right?? Or if you have any ideas on what I should put it would be helpful
Lapatulllka [165]

Answer:

it looks good to me just pay attention to the subscriped, i always have trouble with that.

Explanation:

8 0
3 years ago
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