3. 2 meters per second 4. i think object 7. i’ll try to figure it out 8. .77 9. 25km 10. 10m each second
Answer:
You have to give us an answer choice : )
<h2>Answer:</h2>
Acceleration= -1.11 m/sec²
<h2>Explanation:</h2>
Date Given to us is
Mass = 150 kg
Time = 1.5 minutes = 90 seconds
Distance = 2500 meters
Initial Velocity = 120 m/s
Final Velocity = 20 m/s
Acceleration = ?
<u>Solution:</u>
By using First Equation of motion
Vf = Vi + at
Putting the values
20 = 120 + a (90)
Subtracting 120 on both sides
20-120 = 120 + a(90) - 120
-100 = 90 a
Dividing both sides by 90
-100/90 = 90 a / 90
-1.11 = a
So the acceleration is -1.11 m/s²
Answer:
The normal force applied by block on the ground is (mg - F cosФ)
Explanation:
<em>Lets explain how to solve the problem</em>
At first you must distribute the force F into two components
<em>Vertical</em> component which is <em>F cosФ</em>
<em>Horizontal</em> component which is <em>F sinФ</em>
The block is in equilibrium, that means sum of forces acting on the
block is zero
So the upward forces equal the downward forces
Normal reaction force R applied by block on the ground and the
vertical component of F both are upward forces
The weight of the block is downward force
The normal reaction force R plus the vertical component of F is
equal to the weight
<em>R + F cosФ = W</em>
W = mg, where g is acceleration of gravity and m is the mass of
the block
<em>R + F cosФ = mg</em>
Subtract F cosФ from both sides
<em>R = mg - F cosФ</em>
<em></em>
The normal force applied by block on the ground is (mg - F cosФ)