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Lelechka [254]
3 years ago
12

How many molecules of CO2 are contained in 4.40g of CO2

Chemistry
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

6.02 x 10²²molecules

Explanation:

Given parameters:

Mass of CO₂  = 4.4g

Unknown:

Number of molecules in CO₂  = ?

Solution:

To find the number of molecules in the given mass, we have to find the number of moles in the compound first;

   Number of moles  = \frac{mass}{molar mass}  

Molar mass of CO₂  = 12 + 2(16) = 44g/mol

Insert the parameters and solve;

   Number of moles  = \frac{4.4g}{44g/mol}   =  0.1mol

  1 mole of a substance contains 6.02 x 10²³molecules

  0.1 mole of CO₂ will contain 0.1 x 6.02 x 10²³molecules

                                                 = 6.02 x 10²²molecules

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KengaRu [80]

Moles of H_2O ,

n_{H_2O}=\dfrac{42}{2\times 1 + 16}=\dfrac{42}{18}\\\\n_{H_2O}=2.33\ moles

Moles of acetic acid HCH_3CO_2 ,

n_{A.A}=\dfrac{77}{1 + 12 + 3 + 12 + 16\times 2}=\dfrac{77}{60}\\\\n_{A.A}=1.28\ moles

Mole fraction of water :

M.F_{H_2O}=\dfrac{n_{H_2O}}{n_{H_2O}+n_{A.A}}\\\\M.F_{H_2O}=\dfrac{2.33}{2.33+1.28}\\\\M.F_{H_2O}=0.645

Therefore, mole fraction of water in this solution is 0.645 .

Hence, this is the required solution.

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4 years ago
Does listening to music when you study increase your test scores? What is the independent variable?
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Answer:

It can you just have to find a song that get's stuck in your head and try replacing the studing answer with the song because then the answer will get stuck in your head.

Explanation:

5 0
3 years ago
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What is the empirical formula of a hypothetical compound that is 96%S and 4% H?​
Bess [88]

Explanation:

Let the mass of the compound be 100g.

Mass of Sulfur = 96g.

=> Moles of Sulfur

= 96g / (32.07g/mol) ≈ 3

Mass of Hydrogen = 4g.

=> Moles of Hydrogen

= 4g / (1.008g/mol) ≈ 4

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kakasveta [241]

Answer:

[Ar] 3d10 4s1

Explanation:

The correct electronic configuration of copper is [Ar] 3d10 4s1

Copper has atomic number 29 and due to the stability of half filled or fully filled orbitals or shells, the electrons from the 4s jumps to the 3d and makes the 3d shell contain 10 electrons.

This is what I mean:

Cu = Ar 4s2 3d10 is the expected configuration of copper when we follow the principle of filling the various orbitals that is the s, p, d, f orbitals.

But because we write 3d before writing 4s, we have Ar 3d10 4s2. Instead of this configuration becoming the correct one, an electron from the 4s orbital jumps to the 3d orbital to complete the orbital giving the electrons in the 3d orbital 10.

So therefore the correct configuration is Ar 3d10 4s1

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