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kap26 [50]
3 years ago
8

what will happen to the gravition force between two bodies if the distance between them is halved keeping their masses constant​

Physics
1 answer:
elena55 [62]3 years ago
5 0

Answer:

The new force will be 4times the original

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A robin flies a distance of 45963 cm. How far has it flown in kilometers?
alina1380 [7]

Answer:

0.46km

Explanation:

45963cm/100cm=459.63m/1000m=0.45963 or 0.46km

6 0
3 years ago
How many joules are required to heat .250 kg of liquid water from 0 °C to 100 °C ?
dedylja [7]

Answer:

Specific heat of water is 4.186 J/g/C. The heat required to raise the temperature by

is

Here  is mass of water being heated,  specific heat of water and  change in temperature.

Here .

Heat energy required is

Explanation:

4 0
3 years ago
Ocean currents near the equator are primarily: eastward westward north and south clockwise
sladkih [1.3K]
Equatorial currents are primarily westward. This is because the dominant current in the northern hemisphere has a clockwise direction, while the southern hemisphere has a counterclockwise direction. When these two currents meet at the equator, a common westward current exists.
3 0
4 years ago
Suppose a ball had a potential energy of 5 J when you dropped it.What would be it’s kinetic energy just as it hit the ground?
timama [110]

Answer:

Due to Conservation of Energy just as the ball hits the ground it's potential energy is assumed zero

Therefore disregarding air resistance all energy is converted into potential energy.

So KE = PE  

(5 J)

4 0
3 years ago
Through what voltage must an αα-particle, with its charge of +2e+2e, be accelerated so that it has just enough energy to reach a
mezya [45]

Answer:5101.35v

Explanation:

Radius of gold nucleus=7.3×10-15m and a charge of +79e

Q= 79e

e=1.6×10^-19

q= +2e

The nucleus is considered as the point charge where the potential energy between the charges are

U = 1/(4×3.142×Eo)×(qQ)/r

Where r is distance between the charges and the nucleus

r=R+d

V=U/q

U= 1/(4×3.142×Eo)×Q/r

V= 1/(4×3.142×Eo)×Q/(r+d)

9.0×10^9 ×(79×10^-19)/(7.3×10^-15)+(1.5×10^-14)

V= 9.0×10^9 ×(1.264×10^-17)/(2.23×10^-14)

V= 9×10^9×(5.67×10^-14)= 5101.35v

3 0
4 years ago
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