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2 years ago

A 5000kg truck has 400000J of Kinetic energy. How fast is it moving?

Physics

1 answer:

solong [7]2 years ago

7 0

Answer:

v = √160 m/s

v ≈ 12.65 m/s

Explanation:

KE = ½mv²

v = √(2KE/m)

v = √(2(400000)/5000)

v = √160 m/s

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Monochromatic coherent light shines through a pair of slits. If the wavelength of the light is decreased, which of the following

Law Incorporation [45]

Answer:

he correct answers are a, b

Explanation:

In the two-slit interference phenomenon, the expression for interference is

d sin θ= m λ constructive interference

d sin θ = (m + ½) λ destructive interference

in general this phenomenon occurs for small angles, for which we can write

tanθ = y / L

tan te = sin tea / cos tea = sin tea

sin θ = y / La

derestimate the first two equations.

Let's do the calculation for constructive interference

d y / L = m λ

the distance between maximum clos is and

y = (me / d) λ

this is the position of each maximum, the distance between two consecutive maximums

y₂-y₁ = (L 2/d) λ - (L 1 / d) λ₁ y₂ -y₁ = L / d λ

examining this equation if the wavelength decreases the value of y also decreases

the same calculation for destructive interference

d y / L = (m + ½) κ

y = [(m + ½) L / d] λ

again when it decreases the decrease the distance

the correct answers are a, b

7 0

2 years ago

The near point of an eye is 110 cm. A corrective lens is to be used to allow this eye to focus clearly on objects 26.0 cm in fro

irga5000 [103]

Answer:

The focal length of the lens is 34.047 cm

The power of the needed corrective lens is 2.937 diopter.

Explanation:

Distance of the object from the lens,u = 26 cm

Distance of the image from the lens ,v= -110 cm

(Image is forming on the other side of the lens)

Since ,lens of the human eye is converging lens,convex lens.

Using a lens formula:

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

$\frac{1}{f}=\frac{1}{26 cm}+\frac{1}{-110 cm}$

f = 34.047 cm = 0.3404 m

Power of the lens = P

$P=\frac{1}{f}=\frac{1}{0.34047 m}=2.937 diopter$

6 0

2 years ago

How much work is done by a 120N force applied to a box that moves 5m?

Vsevolod [243]

Answer:

600 Joules

Explanation:

Using the formula F*d*cosФ. Assuming the Ф is parallel to the motion. The work done is 600 Joules.

4 0

2 years ago

A small lead ball, attached to a 1.70-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled

Otrada [13]

Answer:

H = 54.37

Explanation:

given,

lead ball attached at = 1.70 m

rate of revolution = 3 revolution/sec

height above the ground = 2 m

$velocity = \dfrac{distance}{time}$

circumference of the circle = 2 π r

= 2 x π x 1.7

= 10.68 m

$velocity = \dfrac{3 \times 10.68}{1}$

v = 32.04 m/s

using conservation of energy

$\dfrac{1}{2}mv^2 + mgh = mgH$

$\dfrac{1}{2}v^2 + gh = gH$

$\dfrac{1}{2}32.04^2 + 9.8\times 2 = 9.8\times H$

$532.88 = 9.8\times H$

H = 54.37

the maximum height reached by the ball is equal to H = 54.37

4 0

3 years ago

Help please

pychu [463]

The answer should be speed hope this helps

3 0

3 years ago

Read 2 more answers