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3 years ago

ANSWER IS A As you move from left to right across Period 3, which statement is true of the number of

Physics

2 answers:

frosja888 [35]3 years ago

8 0

Answer:

READ YOUR QUESTION CAREFULLY:

If it says left to right, the answer is A. The number of valence electrons increases by 1.

If it says right to left, the answer is B. The number of valence electrons decreases by 1.

Good luck :)

Sedbober [7]3 years ago

7 0

Answer:

A. The number of valence electrons increases by 1.

Explanation:

As you move across any period on the periodic table, the number of valence electrons increases by a value of 1.

The periodic table of elements contains an arrangement of element by their atomic numbers.
From left to right, number of valence electrons increases.
Down a group, the valence electrons are the same.
Across a period, the number of valence electrons increases.

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Hank and Harry are two ice skaters whiling away time by playing 'tug of war' between practice sessions. They hold on to opposite

Alex73 [517]

Answer:

the ratio of Hank's mass to Harry's mass is 0.7937 or [ 0.7937 : 1

Explanation:

Given the data in the question;

Hank and Harry are two ice skaters, since both are on top of ice, we assume that friction is negligible.

We know that from Newton's Second Law;

Force = mass × Acceleration

F = ma

Since they hold on to opposite ends of the same rope. They have the same magnitude of force |F|, which is the same as the tension in the rope.

Now,

Mass $_{Hank$ × Acceleration $_{Hank$ = Mass $_{Henry$ × Acceleration $_{Henry$

Mass $_{Hank$ / Mass $_{Henry$ = Acceleration $_{Henry$ / Acceleration $_{Hank$

given that; magnitude of Hank's acceleration is 1.26 times greater than the magnitude of Harry's acceleration,

Mass $_{Hank$ / Mass $_{Henry$ = 1 / 1.26

Mass $_{Hank$ / Mass $_{Henry$ = 0.7937 or [ 0.7937 : 1 ]

Therefore, the ratio of Hank's mass to Harry's mass is 0.7937 or [ 0.7937 : 1 ]

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3 years ago

A spring that has a spring constant of 1400 N/m is stretched to a length of 2.5 m. If the normal length of the spring is 1.0 m,

Daniel [21]

The answer is 1575, I just took the Review.

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3 years ago

The search for black holes involves searching for The search for black holes involves searching for Group of answer choices sing

trasher [3.6K]

Answer:

Large spherical regions from which no light is detected

Explanation:

A black hole is an object that has an extremely high density such that it possesses very powerful gravitational force that prevents the escape of all objects including light from it, and consumes nearby objects.

Due to the power of the gravitational force of a black hole, at the center, objects are infinitesimally compressed resulting in the inapplicability of the concept of space and time and the location is known as a singularity

Therefore, the search for black holes involves searching for large spherical regions from which no light is detected.

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3 years ago

Honeybees acquire a charge while flying due to friction with the air. A 100 mg bee with a charge of +23 pC experiences an electr

Sedbober [7]

Answer:

(A) ratio of electric force to weight will be $23.469\times 10^{-10}$

(b) Electric field will be $E=4.26\times 10^{10}N/C$

Explanation:

We have given mass of bee = 100 mg = $m=100\times 10^{-3}=0.1kg$

Charge on bee $q=23pC=23\times 10^{-12}C$

Electric field E = 100 N/C

Weight of the bee $W=mg=0.1\times 9.8=0.98N$

Electric force on the bee $F=qE=23\times 10^{-12}\times 100=23\times 10^{-10}N$

So the ratio of electric force on the bee and weight is $=\frac{F}{W}=\frac{23\times 10^{-10}}{0.98}=23.469\times 10^{-10}$

(B) To hold the bee in air electric force must be equal to weight of bee

So $mg=qE$

$0.1\times 9.8=23\times 10^{-12}E$

$E=4.26\times 10^{10}N/C$

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3 years ago

A scientist at a space research center is doing research on near-Earth objects and determining the kinetic energy of a theoretic

Marysya12 [62]

its kinetic energy is 7350kJ


Kinetic energy is given as = $\frac{1}{2} mv^{2}$

Now, m = 12 gms = 0.012 kg
And, velocity = 35 kilometers/second = 35000 m/sec

Kinetic energy is given as = $\frac{1}{2} 0.012 kg * 35000*35000 m/[tex] s^{2}$
= 6 $10^{-2}$ ×1225 × $10^{6}$ m/ $s^{2}$
= 7350 kJ

6 0

4 years ago

Read 2 more answers

** ANSWER IS A** As you move from left to right across Period 3, which statement is true of the number of

ANSWER IS A As you move from left to right across Period 3, which statement is true of the number of