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Elina [12.6K]
3 years ago
7

Solve the following quadratic equation for all values of x in simplest form.

Mathematics
1 answer:
denis-greek [22]3 years ago
8 0

Answer:

x=\sqrt{7},\:x=-\sqrt{7}

Step-by-step explanation:

Start by rewriting the equation to standard form ax^2+bx+c=0.

5(x^2-10)+5=-10,\\5x^2-50+5=-10,\\5x^2-35=0.

Factor out the 5, then isolate x^2:

5x^2-35=0,\\5(x^2-7)=0,\\x^2-7=0,\\x^2=7,\\x=\pm \sqrt{7}..

Therefore, the solutions to this quadratic are:

x=\sqrt{7},\:x=-\sqrt{7}

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Step-by-step explanation:

because we know that angle EOD is less the 90 so that means that it is complementary. For AOB it is  the same but we can check by adding 35 plus x plus 90 =180 degrees  so 35+90=125  x=180-125=55 so x=55 and 55 is less then 90  so it is a complementary angle.

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Step-by-step explanation:

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44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
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Answer:

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Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

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Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

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Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

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Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

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I'm guessing the function is

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