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3 years ago

How many sig figs are in 340.0 mL

Chemistry

2 answers:

lyudmila [28]3 years ago

5 0

Answer:

Explanation:

there is a decimal place present. so you would take away any zeros before the number.

KonstantinChe [14]3 years ago

4 0

Answer:

4 i think

Explanation:

You might be interested in

QveST [7]

Answer:

$- 1.8 \times 10 ^{2} \times 3.4 \times {10}^{3} = - 6.12 \times {10}^{5} \\ \\ = - 6.1 \times {10}^{5}$

I hope I helped you^_^

5 0

3 years ago

Molecules that have the same chemical formula (same numbers of each atom) but different three-dimensional shapes are called ____

Sveta_85 [38]

Answer:

Molecules that have the same chemical formula (same numbers of each atom) but different three-dimensional shapes are called <u>Stereoisomers</u>.

Explanation:

Stereoisomerism is a phenomenon in which molecules have same molecular formula but have different arrangement of atoms or group of atoms in space. It is further classified as;

i) Geometrical Isomerism:

In this class of isomerism the groups or atoms about the double bond occupies different region in space. It is also called as <em>cis-trans </em>isomerism.

ii) Optical Isomerism:

In this class the molecules having same molecular formula differ in their interaction towards plane polarized light.

3 0

4 years ago

How many moles are in 3.14 x 10^25 particles of tin?

lakkis [162]

Answer:

52.1409259 moles.........

5 0

3 years ago

What is difference between groups and periods? 8th grade science idk what to put it under

d1i1m1o1n [39]

One is rows the other is columns

7 0

3 years ago

A chemist designs a galvanic cell that uses these two half-reactions:

Nonamiya [84]

Answer :

(a) Reaction at anode (oxidation) : $4Fe^{2+}\rightarrow 4Fe^{3+}+4e^-$

(b) Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$

(c) $O_2+4H^++4Fe^{2+}\rightarrow 2H_2O+4Fe^{3+}$

(d) Yes, we have have enough information to calculate the cell voltage under standard conditions.

Explanation :

The half reaction will be:

Reaction at anode (oxidation) : $Fe^{2+}\rightarrow Fe^{3+}+e^-$ $E^0_{anode}=+0.771V$

Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$ $E^0_{cathode}=+1.23V$

To balance the electrons we are multiplying oxidation reaction by 4 and then adding both the reaction, we get:

Part (a):

Reaction at anode (oxidation) : $4Fe^{2+}\rightarrow 4Fe^{3+}+4e^-$ $E^0_{anode}=+0.771V$

Part (b):

Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$ $E^0_{cathode}=+1.23V$

Part (c):

The balanced cell reaction will be,

$O_2+4H^++4Fe^{2+}\rightarrow 2H_2O+4Fe^{3+}$

Part (d):

Now we have to calculate the standard electrode potential of the cell.

$E^o=E^o_{cathode}-E^o_{anode}$

$E^o=(1.23V)-(0.771V)=+0.459V$

For a reaction to be spontaneous, the standard electrode potential must be positive.

So, we have have enough information to calculate the cell voltage under standard conditions.

4 0

3 years ago