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Tresset [83]
3 years ago
8

What do you call the energy from earthquakes that propagate through earth as vibrations?​

Physics
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:elastic energy i believe

Explanation:

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Is it possible for an atom to have an electric charge?
jeka57 [31]
False an atom can not have an electric charge.
7 0
3 years ago
Which identifies the energy transformations that take place in Anna’s body as this process takes place?
PtichkaEL [24]

Answer:

Chemical energy is converted to thermal energy and electrical energy.

Explanation:

5 0
3 years ago
Read 2 more answers
Electrons in a particle beam each have a kinetic energy of 4.0 × 10−17 J. What is the magnitude of the electric field that will
denpristay [2]

Explanation:

Relation between work and change in kinetic energy is as follows.

                 W_{net} = \Delta K

Also,   \Delta K = K_{initial} - K_{final}

                        = (0 - 4.0 \times 10^{-17}) J

                        = -4.0 \times 10^{-17} J

Let us assume that electric force on the electron has a magnitude F. The electron moves at a distance of 0.3 m opposite to the direction of the force so that work done is as follows.

                w = -Fd

       -4.0 \times 10^{-17} J = -F \times 0.3 m

                F = 1.33 \times 10^{-16}  

Therefore, relation between electric field and force is as follows.

              E = \frac{F}{q}

                 = \frac{1.33 \times 10^{-16}}{1.60 \times 10^{-19} C}

                 = 0.831 \times 10^{3} C

Thus, we can conclude that magnitude of the electric field that will stop these electrons in a distance of 0.3 m is 0.831 \times 10^{3} C.

3 0
3 years ago
What is the name of the particle that compounds are made of?
VashaNatasha [74]

Answer:

Explanation:

atoms

8 0
3 years ago
The mean distance of an asteroid from the Sun is 2.98 times that of Earth from the Sun. From Kepler's law of periods, calculate
lutik1710 [3]

Answer:

The asteroid requires 5.14 years to make one revolution around the Sun.

Explanation:

Kepler's third law establishes that the square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit:

T^{2} = a^{3} (1)

Where T is the period of revolution and a is the semi-major axis.

In the other hand, the distance between the Earth and the Sun has a value of 1.50x10^{8} Km. That value can be known as well as an astronomical unit (1AU).

But 1 year is equivalent to 1 AU according with Kepler's third law, since 1 year is the orbital period of the Earth.

For the special case of the asteroid the distance will be:

a = 2.98(1.50x10^{8}Km)

a = 4.47x10^{8}Km

That distance will be expressed in terms of astronomical units:

4.47x10^{8}Km.\frac{1AU}{1.50x10^{8}Km} ⇒ 2.98AU

Finally, from equation 1 the period T can be isolated:

T = \sqrt{a^{3}}

T = \sqrt{(2.98)^{3}}  

T = \sqrt{26.463592}

T = 5.14AU

Then, the period can be expressed in years:

5.14AU.\frac{1yr}{1AU} ⇒ 5.14 yr

T = 5.14 yr

Hence, the asteroid requires 5.14 years to make one revolution around the Sun.

8 0
3 years ago
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