Answer:
For the Top Side
- Strain ε = 0.00021739
- Elongation is 0.00260868 cm
For The Right side
- Strain ε = 0.00021739
-Elongation is 0.00347826 cm
Explanation:
Given the data in the question;
Length of the squared titanium plate = 12 cm by 12 cm = 0.12 m by 0.12 m
Thickness = 5 mm = 0.005 m
Force to the Top F
= 15 kN = 15000 Newton
Force to the right F
= 20 kN = 20000 Newton
elastic modulus, E = 115 GPa = 115 × 10⁹ pascal
Now, For the Top Side;
- Strain = σ/E = F / AE
we substitute
= 15000 / ( 0.12 × 0.005 × (115 × 10⁹) )
= 15000 / 69000000
Strain ε = 0.00021739
- Elongation
Δl = ε × l
we substitute
Δl = 0.00021739 × 12 cm
Δl = 0.00260868 cm
Hence, Elongation is 0.00260868 cm
For The Right side
- Strain = σ/E = F / AE
we substitute
Strain = 20000 / ( 0.12 × 0.005 × (115 × 10⁹) )
= 20000 / 69000000
Strain ε = 0.000289855
- Elongation
Δl = ε × l
we substitute
Δl = 0.000289855× 12 cm
Δl = 0.00347826 cm
Hence, Elongation is 0.00347826 cm
A lot of origami used symmetry of paper to create things. And it happens that a lot of things in science can be inferred or easily determined using symmetry. The most recent thing I can think of is exploiting symmetry in Gauss’s Law for electrical flux
Answer:
let number = 0
while number < 1
begin
print "Enter a positive integer: "
read number
end
end_while
find and print number's factors:
let prime = TRUE
let currentFactor = 2
let lastFactor = the square root of number truncated
to an integer value
while currentFactor <= lastFactor
begin
if number is evenly divisible by currentFactor
begin
print currentFactor
let number = number / currentFactor
end
else
let currentFactor = currentFactor + 1
end_if
end
end_while
print a message if number is prime:
if prime == TRUE
print "Your number is prime"
end_if
Explanation:
Answer:
A) initial stored energy = 5x10^-4 J
B) new voltage if space is doubled will be 2000V
C) if space is doubled, stored energy becomes 2x10^-3 J
D) the extra energy comes from the work done in moving the plates further apart
Explanation:
Detailed explanation and calculation is shown in the image below
Answer:
Here is the code in Matlab for the function.
I have also attached the m file for function as well as the test run of the code here and screenshot of the result.
Code:
function [ C ] = columnproduct( A, B )
% get the dimesnions of A
sizeA = size(A);
sizeB = size(B);
% check if columns of A are same as rows of B
if(sizeA(2) ~= sizeB(1))
error('matrix dimensions do not match')
end
% initialize resultant matrix
C = [];
for i = 1:sizeB(2)
% concatenating product of matrix A with each column of B
C = [C A*B(:,i)];
end
end
