Question

Pregunta 5 (1 punto) 1000 grams of (NH4)2S completely react in the following reaction. (NH4)2S(aq) + Sn(SO4)2(aq) 2 (NH4)2SO4(aq) + SnSz(aq) How many grams of SnSz are produced? a 804 grams b 1.89 x 103 grams 947 grams 1.34 x 10grams e 891 grams
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Answer 1

Answer:

N2(g) + 3H2(g) ==> 2NH3(g)  ...  balanced equation

Limiting reactant:

5.44 g N2 x 1 mol/28 g x 2 mol NH3/mol N2 x 17 g NH3/mol = 6.61 g NH3 formed <-- LIMITING = N2(g)

5.58 g H2 x 1 mol/2 g x 2 mol NH3/3 mol H2 x 17 g NH3/mol = 31.6 g NH3 formed

Maximum mass NH3 = 6.61 g

Excess reactant is H2(g)

Mass of excess reagent:

Initial moles H2 = 5.58 g x 1 mol/2 g = 2.79 mol

Moles H2 used up = 5.44 g N2 /28 g x 3 mol H2/mol N2 = 0.583 moles H2 used up

mass H2 remaining = 2.79 mol - 0.583 mol (x2 g/mol) = 4.41 g

I feel i did the wrong thing- I’m only in the 6th grade ;-; I’m so sry if u get this wrong I tried.

Explanation: