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mixas84 [53]
3 years ago
13

Draw a radial power circuit arrangement containing 3 single fused sockets and 2 double unfused sockets showing the live, earth a

nd neutral wiring
Engineering
1 answer:
sweet [91]3 years ago
4 0

Answer:

Attached below is the Radial power circuit arrangement

Explanation:

Radial power circuit arrangement is done in a way that a single cable starts from the fuse box and connects to all the outlet socket contained in the circuit also the cable contains wires ( live , neutral and earth )

The advantage of a radial power circuit arrangement is that it enables easy identification of electrical faults on the circuit.

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Detail a high-end design project and what paper and finishing techniques you would use include your choices for matte or gloss v
DochEvi [55]

Answer   what do you want i know a project but what is it on?

Explanation:

5 0
4 years ago
According to the place-time model of interaction, when people are in the same place, but at different times, this is an example
STALIN [3.7K]

Answer: Shift work communication.

Explanation:

Shift work communication is a type of communication that exist between shift workers, or people at different time zones.

Shift work consists of a three eight hours shift within 24 hours.

Keeping up with a shift work communication requires planning, time management and commitment. It also requires using various communication channels.

3 0
3 years ago
A certain power-supply filter produces an output with a ripple of 100 mV peak-to-peak and a dc value of 20 V. The ripple factor
Oksanka [162]

Answer: the ripple factor is 0.005

Explanation:

Given the data in the question;

we know that expression of ripple factor is;

r = Vr(pp) / Vdc

where Vr(pp) the peak to peak is ripple voltage ( 100mv = 0.1 V)

and Vdc is the dc value of the filter output voltage ( 20 V)

so we substitute our given values;

r = 0.1 / 20

r = 0.005

Therefore; the ripple factor is 0.005

8 0
3 years ago
An adiabatic gas turbine expands air at 1300 kPa and 500◦C to 100 kPa and 127◦C. Air enters the turbine through a 0.2-m2 opening
Viktor [21]

Given:

Pressure, P_{1} = 1300 kPa

Temperature,  T_{1} = 500^{\circ}

P_{2} = 100 kPa

T_{2} = 127^{\circ}  

velocity, v = 40 m/s

A = 1m^{2}

Solution:

For air propertiess at

P_{1} = 1300 kPa

T_{1} = 500^{\circ}

h_{1} = 793kJ/K

v_{1} = 0.172\frac{m^{3}}{kg}

and also at

P_{2} = 100 kPa

T_{2} = 127^{\circ}  

h_{2} = 401 KJ/K

v_{2} =  1.15\frac{m^{3}}{kg}

a) Mass flow rate is given by:

m' = \frac{Av}{v_{1}}

Now,

m = \frac{0.2\times 40}{0.172} = 46.51 kg/s

b) for the power produced by turbine, P = m'(h_{1} - h_{2})

P = 46.51\times(793 - 401) = 18.231 MW

5 0
4 years ago
Please help me I don’t understand
Lapatulllka [165]

Answer:

A battery changes chemical energy to <u>electrical</u> energy

A drum changes mechanical energy to <u>sound</u> energy

Explanation:

A battery is a device that stores chemical energy and converts it to electrical energy.

Beating a drum represents a mechanical to sound energy  conversion.

4 0
3 years ago
Read 2 more answers
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