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snow_tiger [21]
3 years ago
11

Considering this balanced chemical equation, how many grams of HgO will be produced when 44 g of Hg react with excess O2?

Chemistry
1 answer:
lbvjy [14]3 years ago
6 0

Answer:

48g

Explanation:

2Hg(l) + O₂(g) => 2HgO

44g      excess        ?

44g/200.59g·mol⁻¹ = 0.219 mole Hg(l) = 0.219 mole HgO(s) produced.*

*Since coefficients are equal for Hg and HgO then the moles of HgO produced is the same as moles Hg used.

Convert 0.219 mole HgO to grams => 0.219mol x 216.95g/mol = 47.512g HgO ≅ 48g (2 sig figs)

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Please see the answers in the picture attached below.

Explanation:

Please see the step-by-step solution in the picture attached below.

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Answer:

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Explanation:

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