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iogann1982 [59]
3 years ago
12

Salts as neutral, acidic, or basic.? identify the following salts as neutral, acidic, or basic. 2srbr2 4lif

Chemistry
1 answer:
Nuetrik [128]3 years ago
8 0
Acidic salts are those that are products of the reaction between a strong acid and a weak base, while basic salts are produced from reactions between weak acids and strong bases. In neutral salts, the strength of the reacting acid and base are similar.
SrBr₂ is a neutral salt
LiF is a basic salt
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How are mass and volumes alike?
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Kind of this is probably wrong Mass weight of solid, volume weight of liquid?
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4 years ago
In cats,short hair is dominant to long hair. If a heterozygous short-haired cat is crossed with a homozygous long haired cat,wha
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Answer: 50% will have short hair

Explanation: The allele for a heterozygous dominant short hair is ( Ss ) and the allele for the homozygous long hair which is the recessive trait is ( ss ).

If we cross these alleles the results will be.

s s

S Ss Ss

s ss ss

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7 0
3 years ago
A rectangular box has a length of 12 cm, a width of 20 cm, and a
enot [183]

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1100mL

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8 0
3 years ago
Tellurium has eight isotopes: Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), T
Elena-2011 [213]

The average atomic mass of tellurium, calculated from its eight isotopes (Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), Te-128 (31.79%), and Te-130 (34.48%)) is 127.723 amu.

The average atomic mass of Te can be calculated as follows:

A = m_{Te-120}\%_{Te-120} + m_{Te-122}\%_{Te-122} + m_{Te-123}\%_{Te-123} + m_{Te-124}\%_{Te-124} + m_{Te-125}\%_{Te-125} + m_{Te-126}\%_{Te-126} + m_{Te-128}\%_{Te-128} + m_{Te-130}\%_{Te-130}

Where:

m: is the mass

%: is the abundance percent

Knowing all the masses and abundance values, we have:

A = 120*0.09\% + 122*2.46\% + 123*0.87\% + 124*4.61\% + 125*6.99\% + 126*18.71\% + 128*31.79\% + 130*34.48\%

To find the <u>average atomic mass</u> we need to change all the <u>percent values</u> to <u>decimal ones</u>

A = 120*9 \cdot 10^{-4} + 122*2.46 \cdot 10^{-2} + 123*8.7\cdot 10^{-3} + 124*4.61 \cdot 10^{-2} + 125*6.99\cdot 10^{-2} + 126*0.1871 + 128*0.3179 + 130*0.3448 = 127.723

Therefore, the average atomic mass of tellurium is 127.723 amu.

You can find more about average atomic mass here brainly.com/question/11096711?referrer=searchResults

I hope it helps you!

4 0
3 years ago
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