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3 years ago

Please help with this question

Physics

2 answers:

san4es73 [151]3 years ago

7 0

Answer:

That's true

Explanation:

I've gotten it right

Serjik [45]3 years ago

7 0

I believe the answer is true.

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A capacitor is charged by a 150.0-V power supply, then disconnected from the power and connected in series with a 0.280-mH induc

ololo11 [35]

Frequency = 1 / (2π√LC)

Frequency = 1 / (2π · 2.8 x 10⁻⁴ · C)

Frequency = 1 / (1.759 x 10⁻³ · C)

Frequency = (568.4 / C) Hz.

Energy stored in a capacitor = 1/2 C V²

Energy = 1/2 C · 2.25 x 10⁴

Energy = (11,250 · C) Joules

Neither of the answers can be completely specified without knowing the value of the capacitor.

4 0

3 years ago

A coil consists of 200 turns of wire. Each turn is a square of side d = 18 cm, and a uniform magnetic field directed perpendicul

vampirchik [111]

Answer:

Induced emf in the coil, $\epsilon=4.05\ volts$

Explanation:

Given that.

Number of turns in the coil, N = 200

Side of square, d = 18 cm = 0.18 m

The field changes linearly from 0 to 0.50 T in 0.80 s.

To find,

The magnitude of the induced emf in the coil while the field is changing.

Solution,

We know that due to change in the magnetic field, an emf gets induced in the coil. The formula of induced emf is given by :

$\epsilon=\dfrac{d\phi}{dt}$

$\phi$ = magnetic flux

$\epsilon=-\dfrac{d(NBA)}{dt}$

A is the ares of square

$\epsilon=AN\dfrac{d(B)}{dt}$

$\epsilon=AN\dfrac{B_f-B_i}{t}$

$\epsilon=(0.18)^2\times 200 \times \dfrac{0.5-0}{0.8}$

$\epsilon=4.05\ volts$

So, the induced emf in the coil is 4.05 volts. Hence, this is the required solution.

8 0

3 years ago

When should you use a piece of pipe as a leverage extension on the handle on a wrench?

Vesnalui [34]

Answer:

Explanation:

We must never use a piece of pipe as a leverage extension on the handle on a wrench.

Hence option d is correct.

7 0

3 years ago

A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and

notsponge [240]

Answer: 1) 17.65 * 10^-12 C/V; 2) 0.68 V

Explanation: In order to calculate the capacitance of one cylinder capacitor we have to use the following expression:

$C=\frac{2\pi \epsilon o L}{ln (b/a)}$ where and b are the inner and outer radius of teh cylinder, respectively. L is length of the cylinder.

Finally we also kwn that C=Q/ΔV

then we have

ΔV =Q/C

ΔV = 12 * 10^-12/17.65*10^-12= 0.68V

3 0

3 years ago

A boy rides a bike 56 meters. It takes him 8 seconds. What is his speed?

lilavasa [31]

Answer:

7 meters per second or 7 m/s

8 0

3 years ago

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