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Sergio039 [100]
3 years ago
6

A Grignard reagent is prepared by reacting cyclopentanol with first thionyl chloride and then magnesium in ether. The Grignard r

eagent is then reacted with acetaldehyde (ethanal) and the reaction mixture acidified. What is the major final product of this series of reactions?
Chemistry
1 answer:
erastova [34]3 years ago
6 0

Answer:

Grignard reagent is a chemical compound having a halogen group along with magnesium and organic group.

Explanation:

When cyclopentanol reacts with thiogyl chloride, it gives chlorocyclopentane as the product which on further reaction with magnesium metal gives Grigmard reagent as the main product.

A Grignard reagent is a chemical compound which have the chemical formula of R−Mg−X. Here, R is an organic group, Mg is magnesium and X is halogen. The organic group may be aryl or alkyl.

The reaction and the final product is given below at the attachment.

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<span>One mole of a substance contains Avogadro's number of atoms/molecules/the like. This would mean that all of the items described would have approximately 6.022 * 10^23 atoms, even though their masses would differ. This would be due to the molar mass of each substance being different because of the constituent elements in the substance.</span>
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3 years ago
The electron configuration filling patterns of some elements in group 6b(6) and group 1b(11) reflect the ______ of half-filled a
Fudgin [204]

The electron configuration filling patterns of some elements in group 6b(6) and group 1b(11) reflect the increasing stability of half-filled and completely filled sublevels.

<h2>What is electronic configuration?</h2>

The distribution of electrons in an element's atomic orbitals is described by the element's electron configuration. Atomic subshells that contain electrons are placed in a series, and the number of electrons that each one of them holds is indicated in superscript for all atomic electron configurations. For instance, sodium's electron configuration is 1s22s22p63s1.

Almost all of the elements write their electronic configurations in the same style. When the energies of two subshells differ, an electron from the lower energy subshell occasionally goes to the higher energy subshell.

This is due to two factors:

Symmetrical distribution: As is well known, stability is a result of symmetry. Because of the symmetrical distribution of electrons, orbitals where the sub-shell is exactly half-full or totally filled are more stable.

Energy exchange: The electrons in degenerate orbitals have a parallel spin and are prone to shifting positions. The energy released during this process is simply referred to as exchange energy. The greatest number of exchanges occurs when the orbitals are half- or fully-filled. Its stability is therefore at its highest.

To know more about electronic configuration, go to URL

brainly.com/question/26084288

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8 0
2 years ago
In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 30000 J. If mass of the obj
olganol [36]

Answer:

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

Explanation:

Step 1: Data given

Initial temperature = 10.0 °C

Final temperature = 25.0 °C

Energy required = 30000 J

Mass of the object = 40.0 grams

Step 2: Calculate the specific heat capacity of the object

Q = m* c * ΔT

⇒With Q = the heat required = 30000 J

⇒with m = the mass of the object = 40.0 grams

⇒with c = the specific heat capacity of the object = TO BE DETERMINED

⇒with ΔT = The change in temperature = T2 - T2 = 25.0 °C - 10.0°C = 15.0 °C

30000 J = 40.0 g * c * 15.0 °C

c = 30000 J / (40.0 g * 15.0 °C)

c = 50 J/g°C

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

3 0
3 years ago
Suggest one reason why cans are not made entirely from tin
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5 0
3 years ago
Which atom gives up its electrons most easily?<br><br> THE ANSWER IS “Rb”
Sedbober [7]

Answer:

cesium

In particular, cesium (Cs) can give up its valence electron more easily than can lithium (Li). In fact, for the alkali metals (the elements in Group 1), the ease of giving up an electron varies as follows: Cs > Rb > K > Na > Li with Cs the most likely, and Li the least likely, to lose an electron

Explanation:

8 0
3 years ago
Read 2 more answers
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