Answer:
HCO₂H
Explanation:
A buffer is defined as the mixture between a weak acid and its conjugate base, or vice versa, in an aqueous solution.
The HCO₂Na (Sodium formate), is the conjugate base of formic acid, HCO₂H, a weak acid of pKa = 3.75.
Thus, to make a buffer using HCO₂Na, the other substance the buffer should contain is <em>HCO₂H</em>
Answer
its a potassium elements
Explanation:
K 2,8,8,1 period num 4
group 1A
or 1s1 ,2s2 2p6, 3s1
its a metal reacted rapidly with water to form a colorless basic solution of potassium hydroxide (KOH) and hydrogen gas (H2). The reaction continues even when the solution becomes basic. The resulting solution is basic because of the dissolved hydroxide. The reaction is exothermic.
Answer:
C. Lymphocytes
Explanation:
All of the following choices are kinds of white blood cells that have a significant role in the body's immune system.
A. Monocytes
Monocytes defend the body against infection by acting as macrophages. They are capable of eating up foreign bodies that may cause infection.
B. Neutrophils
Neutrophils are the most in number in the body's immune system, especially when there is inflammation. They are distributed to different areas where they can move through circulation along blood vessels. They specifically attack antigens.
C. Lymphocytes
Lymphocytes are further divided into two. These are the B cells and the T cells. The B cells are also of two kinds. One of them is the memory B cells, which can remember a foreign body and create antibodies against it to provide for a long-term resistance in case the body gets exposed to the same infectious agent again.
D. Basophils
As part of the immune system, basophils function for preventing blood clots as well as in mediating allergic reactions.
Answer:
b) [Kr] 5s² 4d¹⁰ 5p⁵
Explanation:
Properties of iodine:
Iodine is present in group seventeen.
It is halogen element.
Its atomic mass is 127 amu.
Its atomic number is 53.
It is present in solid form.
It is crystalline in nature.
It is very corrosive and has pungent odor.
It can not react with oxygen and nitrogen.
Electronic configuration:
I₅₅ = 1s² 2s² 2p⁶ 3s³ 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵
Abbreviated electronic configuration:
I₅₅ = [Kr] 5s² 4d¹⁰ 5p⁵
Abbreviated electronic configuration is shortest electronic configuration by using the noble gases.
Answer:
a) Li2CO3
b) NaCLO4
c) Ba(OH)2
d) (NH4)2CO3
e) H2SO4
f) Ca(CH3COO)2
g) Mg3(PO4)2
f) Na2SO3
Explanation:
a) 2Li + CO3 ↔ Li2CO3
b) NaOH * HCLO4 ↔ NaCLO4 + H2O
c) Ba + 2H2O ↔ Ba(OH)2 +
d) 2NH4 + H2CO3 ↔ (NH4)2CO3 + H2O
c) SO2 + NO2 +H2O ↔ H2SO4 + NOx
f) 2CH3COOH + CaO ↔ Ca(CH3COOH)2 + H2O
g) 3MgO + 2H3PO4 ↔ Mg3(PO4)2 + H2O
h) NaOH + H2SO3 ↔ Na2SO3 + H2O
