B
V= f x lambda
V= 5m/s
F = 10hz
Lambda = ?
5 = 10 x lamba
5 /10 = lambda
Wavelength =0.5
Answer:
When the blood and the dialysate are flowing in the same direction, as the the dialysate and the blood move away from the region of higher concentration of the urea, to a region distant from the source, the concentration of urea in the blood stream and in the dialysis reach equilibrium and diffusion across the semipermeable membrane stops within the higher filter regions such as II, III, IV or V
However, for counter current flow, as the concentration of the urea in the blood stream becomes increasingly lesser the, it encounters increasingly unadulterated dialysate coming from the dialysate source, such that diffusion takes place in all regions of the filter
Explanation:
Answer: a) 0.04kW = 40W
b) 0.05
Explanation:
A)
Thermal efficiency of the power cycle = Input / output
Input = 10 kW + 14,400 kJ/min = 10 kW + 14,400 kJ/(60s) = 10 kW + 14,400/60 kW.
Output = 10 kW
Thermal Efficiency = Output / Input = 10kW / 250kW = 0.04KW = 40W
B)
Maximum Thermal Efficiency of the power cycle = 1 - T1/T2
Where T1 = 285kelvin
And T2 = 300kelvin
Maximum Thermal Efficiency = 1 - T1/T2 = 1 - 285/300 = 0.05
