Surface tension is the inward pull that tends to minimize the surface area of a liquid. Water has high surface tension because o
f hydrogen bonding. In the diagram below, consider a molecule within the bulk of the liquid. This molecule experiences attractions to its neighboring molecules in all directions. These forces, shown by the arrows, average out to zero and there is no net force on the molecule. How is the situation different for a molecule at the surface? How does this give rise to surface tension?
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<h3>Answer:</h3>
2 M
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Unit 0</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<u>Aqueous Solutions</u>
- Molarity = moles of solute / liters of solution
<u>Step 1: Define</u>
36.7 g CaF₂
300 mL H₂O
<u>Step 2: Identify Conversions</u>
Molar Mass of Ca - 40.08 g/mol
Molar Mass of F - 19.00 g/mol
Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol
1000 mL = 1 L
<u>Step 3: Convert</u>
<em>Solute</em>
- Set up:
- Multiply:
<em>Solution</em>
- Set up:
- Multiply:
<u>Step 4: Find Molarity</u>
- Substitute [M]:
- Divide:
<u>Step 5: Check</u>
<em>Follow sig fig rules and round.</em> <em>We are given 1 sig fig as our lowest.</em>
1.56677 M ≈ 2 M
Given that the mass of coffee in the cup = 140 g
Final temperature =
Initial temperature =
Let us assume the specific heat of coffee is equal to that of water = 4.184
Temperature change = T(final) - T(initial) = (20 - 75 )
=- 55
-Heat given out by coffee = heat absorbed by the surroundings
Heat released into the surroundings =-()
=
= 32,217 J