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Elena-2011 [213]
3 years ago
15

when discussing Solutions the amount of solute dissolved in the solvent is important to know as it will affect the colligative p

roperties of a solution a pure illusion prepared by dissolving the maximum amount of solute in a given amount of solvent is best described as​
Chemistry
1 answer:
Mashutka [201]3 years ago
7 0

I hope it helps

thanks you

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The kind of hazardous waste disposal that most clearly resemble recycling is
nydimaria [60]

that would be waste exchange

3 0
3 years ago
Which base would not effectively deprotonate acetylene? (ch3)2nli ch3och2mgbr lioch3 ch3li kh?
Eva8 [605]

Acetylene has a chemical formula which can be written as:

C2H2

 

We can see that there are two positive ions, H+. Now what deprotonation means is that the H+ is removed from acetylene to form acetylene ion and water. In this case, I believe that the answer would be:

<span>LiOCH3</span>

8 0
3 years ago
Read 2 more answers
After the end of a normal inspiration, the volume of air in the lungs is about 2.8 L. Normally quiet inspiration is driven by a
vodka [1.7K]

Answer:

The Volume of the lungs that would produce 2 mmHg pressure decrease is

         V_2 = 2.81 \ L

Explanation:

From the question we are told that

     The volume of air in the lungs is  V = 2.8 \ L

     The pressure difference for quit normal inspiration is P = 2 \ mmHg

      The temperature of air in the lungs T = 37^oC

      The pressure  after normal  expiration is at  T =  760 \ mmHg

     

From ideal gas law we have that

         PV= nRT

Now since  nRT is constant we have that

        P_1 V_1 = P_2 V_2

As the pressure decreased by 2 mmHg the volume becomes

        V_2 = \frac{P_1 V_1}{P_2}

        V_2 = \frac{2.8 * 760}{758}

        V_2 = 2.81 \ L

       

     

3 0
3 years ago
1. How many valence electrons are in an atom of phosphorus? (atomic number 15)
Alinara [238K]
1. D. 5
2. B. 2
3. A. fluroine
Hope this helps you!!
Have a wonderful day!
7 0
4 years ago
Can you name some chemical elements you use or see on a regular basis?
kaheart [24]

Answer:

Hydrogen. Symbol: H. Atomic Weight: 1.008. ...

Magnesium. Symbol: Mg. Atomic Weight: 24.305. ...

Aluminum. Symbol: Al. Atomic Weight: 26.9815385. ...

Phosphorus. Symbol: P. ...

Chlorine. Symbol: Cl. ...

Argon. Symbol: Ar. ...

Potassium. Symbol: K. ...

Calcium. Symbol: Ca.

4 0
3 years ago
Read 2 more answers
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