ANSWER THIS FOR ME!!!! SHOW PROOF

Chemistry

1 answer:

Klio2033 [76]2 years ago

6 0

Answer:

I got you

Explanation:

The answer is C. "Our Sun is the center of a solar system in the Milky Way galaxy. My explanation to this being my answer is that the Andromeda galaxy is the only other galaxy on this list yet it is 2.5 million light years away from Earth and the Sun and plus, the Milky Way is the galaxy that contains our solar system, hope that's enough proof and good luck on whatever your working on! :D

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5. How many moles of gas are in a 7.5 L container, at 1 atm of pressure, at 100 degrees

loris [4]

Answer:

Ok; just use PV=nRT solve for n.

Explanation:

7 0

3 years ago

2Al + 3Br2 --> 2AlBr3

vlada-n [284]

A) The limiting reactant is Al
b) Br2 is the excess reactant
c) The amount moles of AlBr3 that get produced will be equal to the number of moles of Al to begin with.
d) 0

4 0

3 years ago

A chemical engineer is studying the two reactions shown in the table below.

Kamila [148]

Explanation:

Here are the answers. Do note that I had to convert the enthalpy to joules and temperature to Kelvin to make the unit for entropy work out.

4 0

3 years ago

The standard enthalpy change for the following reaction is 873 kJ at 298 K.

Flura [38]

Answer: - 436.5 kJ.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.

The given chemical reaction is,

$2KCl(s)\rightarrow 2K(s)+Cl_2(g)$ $\Delta H_1=873kJ$

Now we have to determine the value of $\Delta H$ for the following reaction i.e,

$K(s)+\frac{1}{2}Cl_2(g)\rightarrow KCl(s)$ $\Delta H_2=?$

According to the Hess’s law, if we divide the reaction by half then the $\Delta H$ will also get halved and on reversing the reaction , the sign of enthlapy changes.

So, the value $\Delta H_2$ for the reaction will be: