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amid [387]
3 years ago
8

Because the current in the equivalent resistor of Sample Problem A

Physics
1 answer:
Serhud [2]3 years ago
4 0

V1= IR1= 0.50×2 = 1 V

V2= IR2= 0.50×4= 2 V

V3= IR3= 0.50×5= 2.5 V

V4= IR4= 0.50×7 = 3.5 V

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If you place 48 cm object 15 m in front of a convex mirror of focal length 5 m, what is the magnification of the image?
Arisa [49]

Answer:

m = 0.25

Explanation:

Given that,

Object distance, u = -15cm

Height of the object, h = 48

Focal length, f = cm

We need to find the magnification of the image.

Let v is the image distance. Using mirror's equation.

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\=\dfrac{1}{5}-\dfrac{1}{(-15)}\\\\=3.75\ cm

Magnification,

m=\dfrac{-v}{u}\\\\=\dfrac{-3.75}{-15}\\\\=0.25

Hence, the magnification of the image is 0.25.

7 0
3 years ago
The volume of a ball was measured at 500.0 cm3, and its mass was measured to be 404.2 g.
KonstantinChe [14]

Answer:

0.8084g/cm³

Explanation:

For calculating density, mass is divided by volume.

Its units is commonly in grams per cubic centimeters.

Therefore,

density= mass/volume

= 404.2/500

=0.8084g/cm³

4 0
3 years ago
Read 2 more answers
Which are functions of the endoplasmic reticulum (ER)?
Oksana_A [137]

Answer:

a. DNA storage

Explanation:

6 0
3 years ago
Isotope A contains 56 protons and 80 neutrons. Isotope B contains 55 protons and 81 neutrons. Isotope C contains 57 protons and
ioda

mass number is defined as sum of number of protons and neutrons

so here for Isotope A

Isotope A contains 56 protons and 80 neutrons.

Mass number will be given as

A = 56 + 80 = 136

For Isotope B

Isotope B contains 55 protons and 81 neutrons.

A = 55 + 81 = 136

For Isotope C

Isotope C contains 57 protons and 80 neutrons.

A = 57 + 80 = 137

For Isotope D

Isotope D contains 56 protons and 74 neutrons.

A = 56 + 74 = 130

<em>So here Isotope A and Isotope B has same mass number</em>

3 0
3 years ago
The beautiful Multnomah Falls in Oregon are approximately 206m high. If the Columbia river is flowing horizontally at 2.90m/s ju
zhenek [66]

Answer:

The overall velocity of the water when it hits the bottom is:

v_f=63.61\ \frac{m}{s}

Explanation:

Use the law of conservation of energy.

Call it instant [1] to the moment when the water is just before reaching the falls.

At this moment its height h is 206 meters and its velocity  horizontally v_i is v_i = 2.90m/s.

At the instant [1] the water has gravitational power energy E_g

E_g = mgh

The water also has kinetic energy Ek.

E_k = 0.5mv_i ^ 2

Then the Total E1 energy is:

E_1 = mgh + 0.5mv_i ^ 2

In the instant [2] the water is within an instant of touching the ground. At this point it only has kinetic energy, since the height h = 0. However at time [2] the water has maximum final velocity v_f

So:

E_2 = 0.5mv_f ^ 2

As the energy is conserved then E_1 = E_2

mgh + 0.5mv_i ^ 2 = 0.5mv_f ^ 2

Now we solve for v_f.

gh + 0.5v_i ^ 2 = 0.5v_f ^ 2\\\\9.8(206) + 0.5(2.90) ^ 2 = 0.5v_f 2\\\\v_f^2 = \frac{9.8(206) + 0.5(2.90) ^ 2}{0.5}\\\\v_f = \sqrt{\frac{9.8(206) + 0.5(2.90) ^ 2}{0.5}}\\\\v_f=63.61\ \frac{m}{s}

7 0
3 years ago
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