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crimeas [40]
3 years ago
6

Which planet is smaller than earth's core?

Chemistry
1 answer:
WINSTONCH [101]3 years ago
3 0
Hello!

 The two smallest major planets, Mercury and Mars, are both smaller than the estimated size of the Earth's core (combined inner and outer core). Mercury has a diameter of about 4879 km and Mars is about 6792 km, compared to the Earth's core which is a sphere about 6972 km in diameter. All of the dwarf planets (Pluto, Eris, Haumea, Makemake, and Ceres) are smaller in diameter than even the Earth's solid inner core (~2440 km in diameter), although Eris is almost as large and Pluto only slightly smaller than Eris. -The Earth's inner core has a thickness (radius) of about 1220 km. -The Earth's outer core has a thickness (radius) of about 2266 km.

Hope this Helps! Have A Wonderful Day! :)
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Consider the following system at equilibrium:A(aq)+B(aq) <---> 2C(aq)Classify each of the following actions by whether it
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Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

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  • On addition of product at equilibrium shifts the equilibrium in backward direction.
  • On removal of reactant at equilibrium shifts the equilibrium in backward direction.
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A(aq)+B(aq)\rightleftharpoons 2C(aq)

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Product = C

1. Increase A

On increasing the amount of A at equilibrium will shift the equilibrium in forward or rightward direction.

2. Increase B

On increasing the amount of B at equilibrium will shift the equilibrium in forward or rightward direction.

3. Increase C

On increasing the amount of C at equilibrium will shift the equilibrium in backward or leftward direction.

4. Decease A

On decreasing the amount of A at equilibrium will shift the equilibrium in backward or leftward direction.

5. Decease B

On decreasing the amount of B at equilibrium will shift the equilibrium in backward or leftward direction.

6. Decease C

On decreasing the amount of C at equilibrium will shift the equilibrium in forward or rightward direction.

7. Double A and Halve B

Equilibrium constant of the reaction = K

K=\frac{[C]^2}{[A][B]}

On doubling A and halving B, equilibrium constant of the reaction = K'

K'=\frac{[C]^2}{[2A][\frac{B}{2}]}=\frac{[C]^2}{[A][B]}

The value of equilibrium constant K' is equal to K, which means that equilibrium will not shift in any direction.

8. Double both B and C

Equilibrium constant of the reaction = K

K=\frac{[C]^2}{[A][B]}

On doubling B and C, equilibrium constant of the reaction = K'

K'=\frac{[2C]^2}{[A][2B]}=\frac{4[C]^2}{[A][2B]}=\frac{2[C]^2}{[A][B]}

K' = 2 K

The value of equilibrium constant K' is double the K, which means that product is increasing which means that equilibrium will shift in backward or leftward direction.

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