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Greeley [361]
2 years ago
8

1. How much work is done by a person if he lifts a load of 500 kg upto a height of 2m?​

Physics
1 answer:
iren [92.7K]2 years ago
3 0

Explanation:

if we take g=9.8m/s^2

F=mg

m=500

F=500×9.8=4900N

h=2

so w=mgh

w=4900×2

=9800j

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Anvisha [2.4K]

Answer:

Energy = 1.38*10^13 J/mol

Explanation:

Total number of proton in F-19 = 9

Total number of neutron in F-19 = 10

Expected Mass of F-19  

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Actual  mass of F-19 = 18.998 u

Energy of one particle of F-19 = 931.5*Δm = 931.5*(19.152-18.998)

= 143.234 MeV

Energy of one mole of F-19 = 143.234*10^6*1.6*10^-19*6.022*10^23  

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3 years ago
Two teams of nine members each engage in tug-of-war. Each of the first team's members has an average mass of 68 kg and exerts an
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Answer:

(a) Acceleration  = 0.1063 m/s^2      (Second team wins)

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Total mass of first team = 68 * 9 = 612 kg

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(b) Since we know the acceleration of the first team (pulling being pulled towards the second team at an acceleration of 0.1063 m/s^2) , we can find out the force required to move them:

Force required for first team = mass of first team * acceleration

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This is the force exerted on the first team through the rope, so the tension in the rope will also be 65.106 N.

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