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blagie [28]
3 years ago
13

The first version of a product, which is built and tested during the third stage of technological design, is called a​

Physics
2 answers:
Dimas [21]3 years ago
8 0

Answer:

The third stage of parturition is called " after-birth".

Explanation:

SIZIF [17.4K]3 years ago
7 0

Answer:

Prototype

Explanation:

It's correct on Edge

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Calculate the time (in seconds) needed for a car to accelerating from 0 m/s to 10 m/s at 5 m/s^2?
bazaltina [42]

Answer: 2 s

Explanation: In order to solve this problem we have to use the formule of the final speed  getting with a constant acceleration, it is given by;

Vfinal=Vo+a*t    where Vo is zero.

so then  t=Vfinal/a = (10 m/s)/5 m/s^2= 2 s

4 0
3 years ago
Consider the following quantities: (1) mass, (2) velocity, (3) charge, and (4) magnetic field strength. Upon which of these quan
DENIUS [597]

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2,3,4

Explanation:

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Which statement best describes the process that produced the ending populations of moths
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C. Light color became an adaptation in the surviving moths? Not fully sure.
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4 years ago
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What phenomena occurs when a researcher’s expectations or preferences about the outcome of the study influence the results obtai
nignag [31]

Answer:

Research bias or Experimenter bias

Explanation:

Research bias or Experimenter bias is the phenomena that results when the researcher's preferences or hopes about the result influences the obtained outcomes.

This can also be explained as a result of the unconscious  and subjective effect of the researcher's hopes on the data used in an experiment or the participants of the experiment or the outcome of the related experiment.

This can be avoided by the researcher by paying attention to the records made by the participants of the experiment and not based the outcome of the experiment on the basis of the his thinking.

5 0
3 years ago
A wildlife photographer uses a moderate telephoto lens of focal length 135 mm and maximum aperture f/4.00 to photograph a bear t
labwork [276]

Answer:

<h3>(A) The width x = 0.24 \times 10^{-3} m</h3><h3>(B) The new width is 1.32 \times 10^{-3} m</h3>

Explanation:

Given :

Focal length f =   135 \times 10^{-3}  m

Maximum aperture D = \frac{f}{4}

Wavelength \lambda = 550 \times 10^{-9} m

(A)

From rayleigh criterion,

  \theta = \frac{1.22 \lambda }{D}

  \theta =\frac{ 1.22 \times 550 \times 10^{-9}  }{33.75 \times 10^{-3} }

  \theta = 1.98 \times 10^{-5} rad

From angle formula,

  x = R\theta

Where R = 12 m ( given in example )

x = 12 \times 1.98 \times 10^{-5} m

x = 23.76 \times 10^{-5}

x = 0.24 \times 10^{-3} m

(B)

We know that \theta is proportional to the x and inversely proportional to the D

so we write the new width, here x is 5.5 times larger than above case

   x = 0.24 \times  10^{-3}  \times \frac{22}{4}

   x = 1.32 \times 10^{-3} m

6 0
3 years ago
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