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Luba_88 [7]
3 years ago
12

< Progress: 19/21 groups Due Jan 15 at 11:55 PM Use the References to access important values if needed for this question. Th

e compound cobalt (II) sulfate forms a hydrate with seven water molecules per formula unit. What are the name and formula of the hydrate
Chemistry
1 answer:
Ierofanga [76]3 years ago
6 0

Answer:

CoSO4.7H2O

Cobalt II tetraoxosulphate VI heptahydrate

Explanation:

According to IUPAC nomenclature, compounds are named systematically.

We were told that there are seven water molecules in each formula unit Hence the correct formula of the compound is CoSO4.7H2O

According to IUPAC system, the metal is first named, followed by its oxidation state in Roman numerals. Then the name of the anion is mentioned as well as the number of water molecules. We have to take into account the correct prefix signifying the number of molecules of water of crystallization.

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3 What is the number located in the top right hand corner of the atomic symbol of an ion with 16 protons, 17 neutrons and 14 ele
siniylev [52]

The number located in the top right corner of the ion is +2

An ion is an atom or group of atoms which possess an electric charge.

The charge on an ion can be obtained by using the following formula:

<h3>Charge = Proton – Electron </h3>

With the above formula, we can obtain the charge of the ion given in the question above as illustrated below:

Proton = 16

Neutron = 17

Electron = 14

<h3>Charge =? </h3>

Charge = Proton – Electron

Charge = 16 – 14

<h3>Charge = +2</h3>

Therefore, the charge on the ion is +2

Learn more: brainly.com/question/3428265

3 0
2 years ago
Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 8.00 g of octane is m
DerKrebs [107]

Answer:

11.3 g of H₂O will be produced.

Explanation:

The combustion is:

2C₈H₁₈ +  25O₂→  16CO₂  +  18H₂O

First of all, we determine the moles of the reactants in order to find out the limiting reactant.

8 g / 114g/mol = 0.0701 moles of octane

37g / 32 g/mol = 1.15 moles of oxygen

The limiting reagent is the octane. Let's see it by this rule of three:

25 moles of oxygen react to 2 moles of octane so  

1.15 moles of oxygen will react to ( 1.15 . 2)/ 25 = 0.092 moles of octane.

We do not have enough octane, we need 0.092 moles and we have 0.0701 moles. Now we work with the stoichiometry of the reaction so we make this rule of three:

2 moles of octane produce 18 moles of water

Then 0.0701 moles of octane may produce (0.0701 . 18)/2= 0.631 moles of water.

We convert the moles to mass → 0.631 mol . 18 g/1mol = 11.3 g of H₂O will be produced.

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Answer:

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Explanation:

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They gain energy , it also allows plants to create organic molecules that they use as fuel.

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