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Luba_88 [7]
3 years ago
12

< Progress: 19/21 groups Due Jan 15 at 11:55 PM Use the References to access important values if needed for this question. Th

e compound cobalt (II) sulfate forms a hydrate with seven water molecules per formula unit. What are the name and formula of the hydrate
Chemistry
1 answer:
Ierofanga [76]3 years ago
6 0

Answer:

CoSO4.7H2O

Cobalt II tetraoxosulphate VI heptahydrate

Explanation:

According to IUPAC nomenclature, compounds are named systematically.

We were told that there are seven water molecules in each formula unit Hence the correct formula of the compound is CoSO4.7H2O

According to IUPAC system, the metal is first named, followed by its oxidation state in Roman numerals. Then the name of the anion is mentioned as well as the number of water molecules. We have to take into account the correct prefix signifying the number of molecules of water of crystallization.

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A sample of nitrogen gas, stored in a 2.96-L container at 32.0°C, exerts a pressure of 4.27 atm. Calculate the number of moles o
inysia [295]

<u>Answer:</u> The number of moles of nitrogen gas is 0.505 moles.

<u>Explanation:</u>

To calculate the number of moles of nitrogen gas, we use ideal gas equation, which is:

PV=nRT

where,

P = pressure of the gas = 4.27 atm

V = Volume of the gas = 2.96 L

T = Temperature of the gas = 32.0^oC=[32.0+273]K=305K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of gas = ?

Putting values in above equation, we get:

4.27atm\times 2.96L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 305K\\n=0.505mol

Hence, the number of moles of nitrogen gas is 0.505 moles.

6 0
4 years ago
Read 2 more answers
If I use 4 N of force to push an object 3 m, how much work have I done? A)3J B)4N C)12J
artcher [175]

Work done by me for using force of 4 N to push an object 3 m away is 12 J.

<u>Explanation:</u>

Work done on any object is defined as the force required to displace that object from its original position. In other terms, the work done is the measure of force utilized for moving an object. So mathematically it is represented as the product of force with the displacement of the object due to that force.

           Work Done = Force \times Displacement

Then, here it is given that force of about 4 N is used to displace the object to 3m. Thus,

            \text { Work Done }=4 \times 3=12 \mathrm{J}

So, 12 J of work is done by me to push an object 3 m away with the force of 4 N.

8 0
3 years ago
What is the buoyant force of a dog that displaces 10 pounds of water?
Troyanec [42]

Answer:

pls answer this link for the answer :D

Explanation:

brainly.com/question/22200936

5 0
3 years ago
Balance the following equation:<br> Sg + F2 --&gt; SF
Tanzania [10]

Answer:

S+ F2 ⇒ SF

S=1

F =2

So S +F2 ......... 2SF

2S + F2 ..........2SF this is a balance equation

S=2 F=2 in left side s=2 F = 2 in rightside

Explanation:⇆

⇒

3 0
3 years ago
Suppose a grill lighter contains 50.0 g of butane. How many grams of butane in the lighter would have to be burned to produce 17
Hitman42 [59]

<span>Answer is: mass of burned butane is 11.6 g.</span>

Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.

m(butane) = 50,0 g.

<span> V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷ Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) : n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) = 0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) = 0,2 mol.<span>
m(C</span>₄H₁₀) = n(C₄H₁₀) · M(C₄H₁₀).<span>
m(C</span>₄H₁₀) = 0,2 mol · 58 g/mol.<span>
m(C</span>₄H₁₀) = 11,6 g.

5 0
4 years ago
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