<u>Answer:</u> The number of moles of nitrogen gas is 0.505 moles.
<u>Explanation:</u>
To calculate the number of moles of nitrogen gas, we use ideal gas equation, which is:

where,
P = pressure of the gas = 4.27 atm
V = Volume of the gas = 2.96 L
T = Temperature of the gas = ![32.0^oC=[32.0+273]K=305K](https://tex.z-dn.net/?f=32.0%5EoC%3D%5B32.0%2B273%5DK%3D305K)
R = Gas constant = 
n = number of moles of gas = ?
Putting values in above equation, we get:

Hence, the number of moles of nitrogen gas is 0.505 moles.
Work done by me for using force of 4 N to push an object 3 m away is 12 J.
<u>Explanation:</u>
Work done on any object is defined as the force required to displace that object from its original position. In other terms, the work done is the measure of force utilized for moving an object. So mathematically it is represented as the product of force with the displacement of the object due to that force.

Then, here it is given that force of about 4 N is used to displace the object to 3m. Thus,

So, 12 J of work is done by me to push an object 3 m away with the force of 4 N.
Answer:
S+ F2 ⇒ SF
S=1
F =2
So S +F2 ......... 2SF
2S + F2 ..........2SF this is a balance equation
S=2 F=2 in left side s=2 F = 2 in rightside
Explanation:⇆
⇒
<span>Answer
is: mass of burned butane is 11.6 g.</span>
Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.
m(butane)
= 50,0 g.
<span>
V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷
Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) :
n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) =
0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) =
0,2 mol.<span>
m(C</span>₄H₁₀) =
n(C₄H₁₀) · M(C₄H₁₀).<span>
m(C</span>₄H₁₀) =
0,2 mol · 58 g/mol.<span>
m(C</span>₄H₁₀) =
11,6 g.