Explanation:
Force of attraction is larger in neon -60°C
Nitrogen fixation is the process that makes atmospheric nitrogen available to plants by mutualistic and free-living bacteria. The process is undertaken by the rhizobium bacteria that live in root roots of plants such as legumes. The mutualistic relationship is that the plant supplies the bacteria with a habitat in which to live, water, and nutrients, and the bacteria supply nitrogen for making plant proteins.
Answer:
The rapid movement of excess charge from one place to another is an <em>electric discharge.</em>
Explanation:
A material in which electrons <em>CANNOT</em> move easily from place to place is an insulator. A material in which electrons <em>CAN </em>move easily from place to place is a conductor.
Answer: False
Explanation: The chemical hazard label indicates the class of harzard of chemical products. It appears on their Safety Data Sheet (SDS), which contains a lot of informations about these substances.
The chemical hazard label is divided into four colors and which one has a meaning (categorie) connected with a number, like:
Blue: Health hazard - If the chemical is deadly (4), extreme danger (3), hazardous (2), slightly hazardous (1) or a normal material (0).
Red: Fire hazard (flammability) - If the chemical has flash point bellow 73ºF (4), bellow 100ºF (3), above 100ºF not exceeding 200ºF (2), above 200ºF (1) or will not burn (0).
Yellow: Reactivity (it can be related to instability) - If the chemical may detonate (4), shock and heat may detonete it (3), if it can suffer a violent chemical change (2) or unstable if heated (1) or if it is stable (0).
White: Specific hazard - If the chemical is acid (ACID) or alkali (ALK), for example.
Answer:
0.129 L = 129.0 mL.
Explanation:
- NaOH neutralizes acetic acid (CH₃COOH) according to the balanced reaction:
<em>NaOH + CH₃COOH → CH₃COONa + H₂O. </em>
- According to the balanced equation: 1.0 mole of NaOH will neutralize 1.0 mole of CH₃COOH.
<em>no. of moles of CH₃COOH = mass/molar mass </em>= (2.0 g)/(60 g/mol) = <em>0.033 mole. </em>
<em>
</em>
no. of moles = (0.258 mol/L)(V)
- At neutralization: no. of moles of NaOH = no. of moles of CH₃COOH
∴ (0.258 mol/L)(V) = 0.033 mole
<em>∴ The volume of NaOH</em> = (0.033 mole)/(0.258 mol/L) = <em>0.129 L = 129.0 mL.</em>
