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Alik [6]
2 years ago
9

Examples of indicator electrodes​

Chemistry
1 answer:
kotegsom [21]2 years ago
3 0

There are several different kinds of indicator electrodes. Several metals, such as silver, copper, lead, cadmium, and mercury, will participate in a reversible electron exchange and can serve as indicator electrodes for their ions.

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when an electron moves from a higher orbit to a lower one does it always follow the same path explained​
Ilia_Sergeevich [38]

Yes, electron follows the same path when it absorb and loses energy.

Yes, when an electron moves from a higher orbit to a lower orbit it always follow the same path as it moves from a lower orbit to a higher orbit. When electron absorb energy it has the power to move from lower orbit to higher orbit or energy level.

While on the other hand, when an electron loses that energy, it comes back to its original position from which it moves earlier when it absorb energy so we conclude that electron follows the same path when it absorb and loses energy.

Learn more: brainly.com/question/24962163

8 0
2 years ago
Read 2 more answers
Which do you think has more mass, 1 mole of fructose, 1 mole of sucrose or 1 mole of aspartame? Explain your reasoning.
pogonyaev

Answer:

i think they would be all the same

Explanation:

they sound like sugars

6 0
2 years ago
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HELP HELP URGENT<br> STRONG ACIDS AND BASES
leonid [27]

Answer:

Solution A is correct.

Explanation:

Strong acids or bases are assumed to dissociate completely when in a aqueous solution.

3 0
3 years ago
During a reaction, the enthalpy of formation of an intermediate is -286
Darina [25.2K]

Answer:

O A. -572 kJ

Explanation:

3 0
2 years ago
In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water: CH4 (g) 2O2
Degger [83]

Answer:

The energy released will be -94.56 kJ or -94.6 kJ.

Explanation:

The molar mass of methane is 16g/mol

The given reaction is:

CH_{4}(g) + 2O_{2} (g) --> CO_{2} (g)+ 2H_{2}O(l)

the enthalpy of reaction is given as  ΔH = -890.0 kJ

This means that when one mole of methane undergoes combustion it gives this much of energy.

Now as given that the amount of methane combusted = 1.70g

The energy released will be:

=\frac{energy released by one moleXgiven mass}{molarmass} =\frac{-890X1.7}{16}= -94.56 kJ

7 0
3 years ago
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