For the steady flow process, the first law is written like
DH + Du2/2 + gDz = Q + Ws
since there is no shaft work, Ws = 0
and flow is horizontal, Dz = 0
Therefore,
DH + Du2/2 = Q
substituting for the quantities,
(2726.5 - 334.9) x 1000 + (200^2 - 3^2)/2 = Q (in terms of J/kg)
Q = 2411.1 kJ/kg
Heat transferred through the coil per unit mass of water = 2411.1 kJ
Explanation:
r^2= 9×10^9 × 5.87×5.87×10^-16 / 64.9
=47.7× 10^-8
so taking sq. root
r = 6.9 ×10^-4 m
or
r= 6.9×10^ -2 cm
this gives the required seperation
Answer:
A. 20 N
Explanation:
weight of book is 2×10=20N .....
The answer is 2000 I need 20 characters do djrjrkrir
Answer:
According to Newton's third law of motion to every action, there is an equal and opposite reaction. When a rocket moves in free space it ejects hot gases. ... It is then the “reaction force”. As a result, the rocket is accelerated or propelled in the opposite direction.
Launching a rocket relies on Newton's Third Law of Motion. A rocket engine produces thrust through action and reaction. The engine produces hot exhaust gases which flow out of the back of the engine. In reaction, a thrusting force is produced in the opposite reaction.