Answer:
<em>The energy of an individual photon that comes out of the laser pointer is 1.91 eV</em>
Explanation:
The energy of a photon can be obtained using the expression below
E = hc/λ
where E is the energy;
h is the Planck's constant = 6.626 x 10-34 Js;
c is the speed of light = 3.00 x m/s (speed of light);
λ is the wavelength = 650 nm =650 x m.
E = (6.626 x 10-34 Js) x (3.00 x m/s) /650 x m
E = 3.058 x J
1 joule = 6.242 x eV
3.058 x J = 3.058 x J x 6.242 x eV = 1.91 eV
Therefore the energy of an individual photon that comes out of the laser pointer is 1.91 eV
The Gravitational PE (U) depends on three things: the object’s mass (m), its height (h), and gravitational acceleration (g), which is 9.81 m/s^2 on Earth’s surface.
so U = mgh = 9.81mh on earth
mass of the car = 50.0 grams = 0.05kg
height, h:
Hill 1 = 90.0 cm = 0.9m,
Hill 2 = 65.0 cm = 0.65m,
Hill 3 = 20.0 cm = 0.2m
substitute into eqn U = mgh
U @ top of Hill 1 = 0.05*9.81*0.9 = 0.4415J
U @ top of Hill 2 = 0.05*9.81*0.65 = 0.3188J
U @ top of Hill 3 = 0.05*9.81*0.2 = 0.0981J
difference in Gravitational Potential Energy from the top of Hill 1 to the top of Hill 3 = 0.4415 - 0.0981
= 0.3434J where J is the unit for energy, Joules
For this case, the relationship between the two forces is given by:
F1 = nF2
Where,
- F1: output strength
- F2: input force
- n: mechanical advantage
Then, replacing the values we have:
F1 = (2.2)(202)
Having the calculations we have:
F1 = 444.4N
Answer: The output force that only lifts the load is F1 = 444.4N.