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3 years ago

Why are poisons used less today than they were in the past? What factors influenced this change.

Chemistry

1 answer:

Natali5045456 [20]3 years ago

4 0

Answer:

Poisons are used less today than they were in the past because forensic scientists can easily detect many substances and toxins during an autopsy.

The main factor that influenced this change is advancements in forensic toxicology knowledge and technology.

good luck, i hope this helps :)

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Ch4+202==>c02+302 what type of chemical reaction

n200080 [17]

Answer:

First of all, the equation is typed wrong so it can easily be misinterpreted

Ethane (CH4) + Oxygen gas (O2) would give us Carbon Dioxide (CO2) and WATER (H2O)

CH4 + 2O2 -----> CO2 + 2H2O

And this is a combustion reaction since we have oxygen as a reactant and carbon dioxide and water as products.

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3 years ago

If you are asked to compare matter in solid, liquid, and gaseous states, which statement best defines a gas?

Elza [17]

I am pretty sure that If I were asked to compare matter in solid, liquid, and gaseous states, the statement which would best defined a gas is highest energy, highest molecular motion, and least dense packaging of molecules. I choose this one because it's not sensible to heat CO2 (in case of safety) and in the last option the amount of energy is not satisfying.

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3 years ago

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If the number of atoms of each element on the reactant side of an equation is equal to the number of atoms of each element on th

cricket20 [7]

C. Is your answer hope you have a wonderful day

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3 years ago

a chemist determined by measurements that 0.015 moles of tungsten participated in a chemical reaction. Calculate the mass of tun

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Explanation:

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3 years ago

Find the pH. What are the pH values for the following solutions? (a) 0.1 M HCl (b) 0.1 M NaOH (c) 0.05 M HCl (d) 0.05 M NaOH

slega [8]

Answer:

(a) $pH=1$

(b) $pH=1.3$

(d) $pH=12.7$

Explanation:

Hello,

In this case, we define the pH in terms of the concentration of hydronium ions as:

$pH=-log([H^+])$

Which is directly computed for the strong hydrochloric acid (consider a complete dissociation which means the concentration of hydronium equals the concentration of acid) in (a) and (c) as shown below:

(a)

$[H^+]=[HCl]=0.1M$

$pH=-log(0.1)=1$

(b)

$[H^+]=[HCl]=0.05M$

$pH=-log(0.05)=1.3$

Nevertheless, for the strong sodium hydroxide, we don't directly compute the pH but the pOH since the concentration of base equals the concentration hydroxyl in the solution:

$[OH^-]=[NaOH]$

$pOH=-log([OH^-])$

$pH=14-pOH$

Thus, we have:

(b)

$pOH=-log(0.1)=1\\pH=14-1=13$

(d)

$pOH=-log(0.05)=1.3\\pH=14-1.3=12.7$

Best regards.

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3 years ago