The volume is 19.76987448 by taking the known variables mass=18.9g and density=0.956g/ml
To get volume you divide the mass by the density which gives you about
19.77 ml in volume
-OH is elctron donating -C=-N is electron withdrawing -O-CO-CH3 is electron withdrawing -N(CH3)2 is electron donating -C(CH3)3 is electron donating -CO-O-CH3 is electron withdrawing -CH(CH3)2 is electron donating -NO2 is electrong withdrawing -CH2
Answer:
A) Ethanoic acid and ammonium chloride.
Explanation:
Amides go through acid hydrolysis to produce carboxylic acid and ammonia by heating in aqueous acid. The acid hydrolysis reaction is produced through the <u>nucleophilic addition of water to the protonated amide</u>, then comes the transference of a proton from the oxygen to the nitrogen to make nitrogen a better leaving group, and finally, the subsequent elimination (see attachment).
In this case, the products formed with the reaction of ethanamide and aqueous HCl will be <u>ethanoic acid and ammonium chloride</u>.
Answer:
Explanation:
Are there any awnser choices?
As a result, the greatest number of an atom's oxidation state will gradually rise over each period of the periodic table. For instance, the third period's highest value of the oxidation number will fall between 1 and 7.
- The Periodic Table only consistently varies the oxidation numbers of Group 1 and Group 2 metals in their compounds, which are always +1 and +2, respectively.
- Elements have an increasing number of valence electrons that can range from 1 to 8 and move from left to right over time. However, when H or O are added to an element first, the element's valency rises to 4, then falls to zero.
<h3>What causes a rise in the oxidation number?</h3>
An increase in oxidation number results from the loss of negatively charged electrons, whereas a reduction in oxidation number results from the gain of electrons. The result is a rise in the oxidation number of the oxidized element or ion.
<h3>Pattern of the Period 2?</h3>
The trends in Period 2 are significantly more clear-cut. All elements in period 2 experience a decrease in atomic radius, an increase in electronegativity, and an increase in ionization energy as their atomic number rises.
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