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ra1l [238]
3 years ago
6

You are discussing a material that has a strong resistance to the flow of electrons. This is a description of a(n)

Physics
2 answers:
cupoosta [38]3 years ago
5 0
C. Insulator

It COULD be semi-insulator but i'm sure its C
eimsori [14]3 years ago
4 0
Insulator. the right answer'
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Consider a current carrying a wire coming out of your computer screen towards you. Which statement below correctly describes the
Ugo [173]

Answer:

1. The magnetic field encircles the wire in a counterclockwise direction

Explanation:

When we have a current carrying wire perpendicular to the screen in which the current flows out of the screen then by the Maxwell's right-hand thumb rule we place the thumb of our right hand in the direction of the current and curl the remaining fingers around the wire, these curled fingers denote the direction of the magnetic field which is in the counter-clock wise direction.

Ever current carrying conductor produces a magnetic field around it.

5 0
3 years ago
The highest element in the hierarchical breakdown of the wbs is
Makovka662 [10]
Work package. Hope this helps!
5 0
3 years ago
1.) I’m bored, so I decide to play catch by myself. I throw a 1.5kg ball in the air at 25 m/s. How long do I have to wait to cat
navik [9.2K]

Answer:

technically yes

Explanation:

with a gun depending on how fast it shoots so when you fire at something you shoot in front of it a little bit so you hit it but a plane that fast you shoot like 100 feet infront of it...

4 0
3 years ago
Read 2 more answers
What is the density of a piece of quartz with a mass of 30g and a volume of 6cm^3
FromTheMoon [43]

Answer:

\boxed {\boxed {\sf d= 5 \ g/cm^3}}

Explanation:

Density can be found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the quartz is 30 grams and the volume is 6 cubic centimeters.

m=30 \ g \\v= 6 \ cm^3

Substitute the values into the formula.

d=\frac{30 \ g}{6 \ cm^3}

Divide.

d= 5 \ g/cm^3

The density of this piece of quartz is 5 grams per cubic centimeter.

7 0
3 years ago
What must be the magnitude of a uniform electric field if it is to have the same energy density as that possessed by a 0.50 T ma
Sindrei [870]

Answer:

E = 1.50 × 10^{8} V/m

Explanation:

given data

B = 0.50 T

solution

we know that energy density by the magnetic field is express as

\mu _b = \frac{B}{2\mu _o}   ...............1

and

energy density due to electric filed is

\mu _e = \frac{\epsilon _o E^2}{2}     ...............2

and here \mu _b = \mu _ e

so that

E = \frac{B}{\sqrt{\mu _o \times \epsilon _o}}      ...................3

put here value and we get

E = \frac{0.50}{\sqrt{4\pi \times 10^{-7} \times 8.852 \times 10^{-12}}}  

E = 3 × 10^{8}  × 0.50

E = 1.50 × 10^{8} V/m

6 0
3 years ago
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