The number of moles of gas present are 0.0054
<u>Explanation:</u>
Given-
Temperature, T = 100°C = 100 + 273 = 373K
Volume, V = 0.044L
Pressure, P = 3.81 atm
Moles of gas, n = ?
We know,
PV = nRT
R = 0.082 L.atm.K⁻¹.mol⁻¹
n = PV/RT
n = (3.81)(0.044)/(0.082)(373)
n = 0.0054 moles
Therefore, number of moles of gas present are 0.0054
Indirect relationship: relationship between two variables which move in opposite directions.
If temperature decreases, number of spiders would increase.
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Answer:
Explanation:
2Al(s) + 3 I₂(s) → 2 Al⁺³ + 6 I⁻
Aluminium is oxidised and iodine is reduced .
so cell potential = Ereduction - Eoxidation
Al⁺³ + 3e = Al - 1.66 V
I₂ + 2 e = 2 I⁻ 0.54 V
= .54 - ( - 1.66 )
= 1.66 + .54
= 2.2 V
Answer:
1 g
Explanation:
Given data:
Volume of solution = 250 mL (250 mL × 1 L/1000 mL = 0.25 L)
Molarity of solution = 0.1 M
Amount of sodium hydroxide = ?
Solution:
Molarity = number of moles / volume in L
0.1 M = number of moles /0.25 L
Number of moles = 0.1 M × 0.25 L
M = mol/ L
Number of moles = 0.025 mol
Mass of sodium hydroxide:
Mass = number of moles × molar mass
Mass = 0.025 mol ×40 g/mol
Mass = 1 g