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love history [14]
2 years ago
11

When HCl(g) reacts with NH3(g) to form NH4Cl(s), 42.1 kcal of energy are evolved for each mole of HCl(g) that reacts. Write a ba

lanced equation for the reaction with an energy term in kcal as part of the equation.
Chemistry
1 answer:
stich3 [128]2 years ago
8 0

<u>Answer:</u> The chemical equation is HCl(g)+NH_3(g)\rightarrow NH_4Cl(s)+42.1kCal

<u>Explanation:</u>

There are 2 types of reactions that are classified based on enthalpy change:

  • Endothermic reaction
  • Exothermic reaction

Endothermic reactions: They are defined as the reactions where heat is absorbed by the reaction. The change in enthalpy of the reaction is always positive.

Exothermic reactions: They are defined as the reactions where heat is released by the reaction. The change in enthalpy of the reaction is always negative.

Given values:

Energy released for 1 mole of HCl reacted = -42.1 kCal

The chemical equation for the formation of ammonium chloride follows:

HCl(g)+NH_3(g)\rightarrow NH_4Cl(s)+42.1kCal

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Answer: 27.09 ppm and 0.003 %.

First, <u>for air pollutants, ppm refers to parts of steam or gas per million parts of contaminated air, which can be expressed as cm³ / m³. </u>Therefore, we must find the volume of CO that represents 35 mg of this gas at a temperature of -30 ° C and a pressure of 0.92 atm.

Note: we consider 35 mg since this is the acceptable hourly average concentration of CO per cubic meter m³ of contaminated air established in the "National Ambient Air Quality Objectives". The volume of these 35 mg of gas will change according to the atmospheric conditions in which they are.

So, according to the <em>law of ideal gases,</em>  

PV = nRT

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The moles of CO will be,

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→ n = 0.00125 mol

We clear V from the equation and substitute P = 0.92 atm and

T = -30 ° C + 273.15 K = 243.15 K

V =  \frac{0.00125 mol x 0.082057 \frac{atm L}{mol K}  x 243 K}{0.92 atm}

→ V = 0.0271 L

As 1000 cm³ = 1 L then,

V = 0.0271 L x \frac{1000 cm^{3} }{1 L} = 27.09 cm³

<u>Then the acceptable concentration </u><u>c</u><u> of CO in ppm is,</u>

c = 27 cm³ / m³ = 27 ppm

<u>To express this concentration in percent by volume </u>we must consider that 1 000 000 cm³ = 1 m³ to convert 27.09 cm³ in m³ and multiply the result by 100%:

c = 27.09 \frac{cm^{3} }{m^{3} } x \frac{1 m^{3} }{1 000 000 cm^{3} } x 100%

c = 0.003 %

So, <u>the acceptable concentration of CO if the temperature is -30 °C and pressure is 0.92 atm in ppm and as a percent by volume is </u>27.09 ppm and 0.003 %.

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