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3 years ago

Describe the PURPOSE of Moh's hardness scale. (What information does it tell you)

1 answer:

6 0

Answer: The Mohs Hardness Scale is used as a convenient way to help identify minerals. A mineral's hardness is a measure of its relative resistance to scratching, measured by scratching the mineral against another substance of known hardness on the Mohs Hardness Scale.

Explanation: Hope this helped! :)

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A single alkyl bromide reactant theoretically yields either of the given products, depending on the reaction conditions. Draw th

Ierofanga [76]

Answer:

$H_{3}C$ -- $H_{3}C$ -- $CH_{3}$ --Br-- $CH_{3}$

Explanation:

The steps involved in predicting the structure of the alkyl bromide compound are outlined below.

1) An examination of the product shows that the product could only be formed by a substitution reaction.

2) The structure of the alkyl bromide compound can be then predicted by replacing the methoxide group in the product after the substitution of bromine atom. This is because the methoxide ion acts as a strong nucleophile.

Therefore, by consideration the reaction mechanisms of reactions 1 and 2, it can be predicted that the structure of the alkyl bromide compound is $H_{3}C$ -- $H_{3}C$ -- $CH_{3}$ --Br-- $CH_{3}$ . A pictorial diagram of the alkyl bromide compound is also attached.

8 0

3 years ago

Read 2 more answers

An iceberg has a volume of 8925 ft3. is the mass in kilograms of the iceberg?

Novay_Z [31]

In chem it usually would be but it depends on your units and the instructions

6 0

3 years ago

One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO: 4NH3 (g) 5O2 (g

madreJ [45]

Answer:

O2 is the limiting reactant.

Explanation:

Step 1: Data given

Mass of NH3 = 2.00 grams

Mass of O2 = 2.50 grams

Molar mass NH3 = 17.03 g/mol

Molar mass O2 = 32 g/mol

Step 2: The balanced equation

4NH3(g) + 5O2 (g) → 4NO(g) + 6H2O (g)

Step 3: calculate moles NH3

Moles NH3 = mass NH3 / molar mass NH3

Moles NH3 = 2.00 grams / 17.03 g/mol

Moles NH3 = 0.117 moles

Step 4: Calculate moles O2

Moles O2 = mass / molar mass O2

Moles O2 = 2.50 grams / 32 g/mol

Moles O2 = 0.0781 moles

Step 5: Calculate the limiting reactant

For 4 moles NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed. (0.0781 moles). NH3 is in excess. There will react 4/5 * 0.0781 moles = 0.0625 moles

There will remain 0.117 - 0.0625 = 0.0545 moles NH3

O2 is the limiting reactant.

8 0

3 years ago

PLEASE HELP URGET!!!!

strojnjashka [21]

Answer:

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Explanation:

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5 0

2 years ago

Billions of pounds of urea are produced annually for use as a fertilizer. Balance the skeletal equation for the synthesis of ure

klio [65]

2NH₃(g) + CO₂(g) → CO(NH₂)₂(s) + H₂O(l)
is the balanced equation for the synthesis of urea.

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3 years ago