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ddd [48]
3 years ago
15

I need help with this question please

Mathematics
1 answer:
german3 years ago
8 0

Answer:

C.

Step-by-step explanation:

Given

A =(x_1,y_1)

B =(x_2,y_2)

C =(x_3,y_3)

D =(x_4,y_4)

Required:

Which condition proves that AB is perpendicular to CD

First, calculate the slopes of both.

<u>For AB</u>

m_1 = \frac{y_2 -y_1}{x_2 - x_1}

<u>For CD</u>

m_2 = \frac{y_4 -y_3}{x_4 - x_2}

The condition of perpendicularity is:

m_1 * m_2 = -1

Substitute values for m1 and m2

\frac{y_2 -y_1}{x_2 - x_1} * \frac{y_4 -y_3}{x_4 - x_2} = -1

Option (c) is correct

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21

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4 years ago
The expression two square root of three minus square root of 27 is equivalent to
never [62]

Answer:

-0.954(rounded)

Step-by-step explanation:

first write it in number form

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Suppose a NBA basketball player has 5% chance of picking up a foul every minute he plays. What is the probability that he will p
alukav5142 [94]

Answer:

He wont foul out with probability 0.9093

Step-by-step explanation:

The total number of fools he picked is a Binomial ditribution noted by X with parameters p = 0.05 and N = 48. The mean of this random variable is μ = np = 48*0.05 = 2.4 and the variance is σ² = np(1-p) = 2.4*0.95 = 2.28, hence its standard deviation is σ = √2.28 = 1.51.

Note that, if approximate probability is asked, we could just approximate X with a Normal random variable with mean 2.4 and standard deviation 1.51 (this can be done because of the central limit theorem). We will calculate the probability manually. He wont foul out if he picks 0,1,2,3 or 4 fouls, thus

P(X \leq 4) = P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4) \\= 0.95^{48}+48*0.95^{47}*0.05+{48 \choose 2}*0.95^{46}*0.05^2+\\{48 \choose 3}*0.95^{45}*0.05^3+{48 \choose 4}*0.95^{44}*0.05^4 \\= 0.085+0.215+0.266+0.215+0.127 = 0.9093

As a consecuence, he wont foul out with probability 0.9093.

8 0
4 years ago
Round to the nearest tenth if necessary.
mojhsa [17]
A is 2
B is 4 ft
C is 6 ft
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3 years ago
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