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BaLLatris [955]
3 years ago
11

A building wall has dimensions of 3 m tall and 10 m wide. It is constructed of 2 cm. wallboard (k = 0.5 W/m-C) on the inside, 3

cm. of loose fill mineral wool (k = 0.052 W/m-C), and 10 cm. thick brick (0.7 W/m-C). The inside room temperature is 22 C and the outside air is -20 C. The inside heat transfer coefficient is 8 W/m2-C and the outside coefficient is 32 W/m2- C. a. Determine the wall heat loss (W). b. Draw the temperature profile from the inside room to the outside. Be qualitative in your drawing, no numbers necessary except for the inside and outside temperature.

Engineering
1 answer:
Art [367]3 years ago
4 0

Answer: heat loss through wall is 16.58034kW

Temperature of inside wall surface is 47°c

Temperature of outside wall surface is -2.7°c

Explanation:detailed calculation and explanation is shown in the image below.

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By using a book of the OHS Act, Act 85 of 1993, find the act or regulation where the following extraction comes from "every empl
AnnyKZ [126]

Answer:

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3 0
3 years ago
I am trying to create a line of code to calculate distance between two points. (distance=[tex]\sqrt{ (x2-x1)^2+(y2-y1)^2}) My li
k0ka [10]

Answer:

point_dist = math.sqrt((math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2))

Explanation:

The distance formula is the difference of the x coordinates squared, plus the difference of the y coordinates squared, all square rooted.  For the general case, it appears you simply need to change how you have written the code.

point_dist = math.sqrt((math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2))

Note, by moving the 2 inside of the pow function, you have provided the second argument that it is requesting.

You were close with your initial attempt, you just had a parenthesis after x1 and y1 when you should not have.

Cheers.

6 0
3 years ago
Seawater containing 3.50 wt% salt passes through a series of 11 evaporators. Roughly equal quantities of water are vaporized in
statuscvo [17]

Answer: the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr

Explanation:

F, W and B are the fresh feed, brine and total water obtained

w = 2 x 10^4 L/h

we know that

F = W + B

we substitute

F = 2 x 10^4 + B

F = 20000 + B .................EQUA 1

solute

0.035F = 0.05B

B = 0.035F/0.05

B = 0.7F

now we substitute value of B in equation 1

F = 20000 + 0.7F

0.3F = 20000

F = 20000/0.3

F = 66666.67 kg/hr

B = 0.7F

B = 0.7 * F

B = 0.7 * 66666.67

B = 46,666.669 kg/hr

the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr

8 0
4 years ago
A cylindrical container is 150mm in diameter and weights 2.25n when empty
stellarik [79]

Answer:

.

Explanation:

.

3 0
3 years ago
Environmental assessments (EAs) are an important component of any civil engineering project. Delgado Engineering has been contra
Tom [10]

Answer:

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6 0
3 years ago
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