Step-by-step explanation:
Given,
length of rectangle(l)= 8cm
area of rectangle(A) = 48cm2
breadth of rectangle(b) = ?
Perimeter of rectangle (P)=?
We know ,
Area of rectangle(A) = l×b
or, 48cm2 = 8cm×b
or, 48cm2 = 8bcm
or, 48cm2/8cm = b
or, 6cm = b
or, b = 6cm
therefore, b = 6cm
Perimeter of rectangle (P) = 2(l+b)
= 2(8cm+6cm)
= 2×14cm
= 28cm
therefore, Perimeter of rectangle(P) = 28cm
Now,
According to the question,
Perimeter of rectangle(P) = Perimeter of square(P)
So,
Perimeter of square(P) = 28cm
length of square(l) = ?
Area of square (A) = ?
We know,
Perimeter of square (P) = 4l
or, 28cm = 4l
or, 28cm/4 = l
or, 7cm = l
or, l = 7cm
therefore, l = 7cm
Now,
Area of square (A) = l^2
= (7cm)^2
= 7cm×7cm
= 49cm^2
therefore, area of square (A)= 49cm^2
Answer: 5
Work Shown:
f(x) = 2x+1
f(2) = 2*2+1 ... x has been replaced with 2
f(2) = 4+1
f(2) = 5
The input is x = 2. The output is y = 5.
Answer:
it is 6cm2
Step-by-step explanation:
because see how many faces does it have
